A thick lens has two symmetrical spherical surface (r = -r2 = 3cm) and center thickness of t = 2cm. The refraction index of the lens is n, = 1.5. The lens is placed in air (na = 1.0). A small object has height of h front surface of the lens is d %3| = 2mm above the optical axis of the lens. The distance between object and the = 4cm. Please using ray transfer matrix (RTM) method to compute: 1) Image position (d') and image height (h'). 2) Describe whether this is a real (or virtual), upright (or inverted), and magnified (or reduced) image.

College Physics
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Chapter1: Units, Trigonometry. And Vectors
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A thick lens has two symmetrical spherical surface (r, = -r, = 3cm) and center thickness
of t = 2cm. The refraction index of the lens is n, = 1.5. The lens is placed in air (na = 1.0). A small
object has height of h = 2mm above the optical axis of the lens. The distance between object and the
front surface of the lens is d
4cm. Please using ray transfer matrix (RTM) method to compute:
1) Image position (d') and image height (h').
2) Describe whether this is a real (or virtual), upright (or inverted), and magnified (or reduced) image.
Transcribed Image Text:A thick lens has two symmetrical spherical surface (r, = -r, = 3cm) and center thickness of t = 2cm. The refraction index of the lens is n, = 1.5. The lens is placed in air (na = 1.0). A small object has height of h = 2mm above the optical axis of the lens. The distance between object and the front surface of the lens is d 4cm. Please using ray transfer matrix (RTM) method to compute: 1) Image position (d') and image height (h'). 2) Describe whether this is a real (or virtual), upright (or inverted), and magnified (or reduced) image.
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