When mixed, solutions of barium chloride, BaCl₂, and potassium chromate, K₂CrO4, form a yellow precipitate of barium chromate, BaCrO4. The balanced equation is: BaCl₂(aq) + K₂CrO4(aq) → BaCrO4(s) + 2KCl(aq) How many grams of barium chromate are expected when a solution containing 0.74 mol BaCl₂ is mixed with a solution containing 0.15 mol K₂CrO4? g BaCrO₂

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When mixed, solutions of barium chloride, BaCl2, and potassium chromate, K₂CrO4, form a yellow
precipitate of barium chromate, BaCrO4. The balanced equation is:
BaCl₂(aq) + K₂CrO4(aq) →→ BaCrO4(s) + 2KCl(aq)
-
How many grams of barium chromate are expected when a solution containing 0.74 mol BaCl₂ is mixed
with a solution containing 0.15 mol K₂CrO4?
g BaCrO4
Guide
Transcribed Image Text:Enter your answer in the provided box. When mixed, solutions of barium chloride, BaCl2, and potassium chromate, K₂CrO4, form a yellow precipitate of barium chromate, BaCrO4. The balanced equation is: BaCl₂(aq) + K₂CrO4(aq) →→ BaCrO4(s) + 2KCl(aq) - How many grams of barium chromate are expected when a solution containing 0.74 mol BaCl₂ is mixed with a solution containing 0.15 mol K₂CrO4? g BaCrO4 Guide
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