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An excess volume of 0.10 M BaCl2(aq) is mixed with 1.0 L of Na2SO4(aq) and forms 2.33 g of precipitate. What is the net ionic equation for the reaction?   Ba2+(aq) + SO42–(aq) → BaSO4(s)   2 Na+(aq) 2 Cl–(aq)  →      2 NaCl(s)   2 Na+(aq) 2 Cl–(aq) + Ba2+(aq) +  SO42–(aq) → 2 NaCl(s) + BaSO4(s) What is the minimum volume of BaCl2(aq) added to yield the precipitate?   0.001 L   0.01 L   0.10 L

An excess volume of 0.10 M BaCl2(aq) is mixed with 1.0 L of Na2SO4(aq) and forms 2.33 g of precipitate. What is the net ionic equation for the reaction?   Ba2+(aq) + SO42–(aq) → BaSO4(s)   2 Na+(aq) 2 Cl–(aq)  →      2 NaCl(s)   2 Na+(aq) 2 Cl–(aq) + Ba2+(aq) +  SO42–(aq) → 2 NaCl(s) + BaSO4(s) What is the minimum volume of BaCl2(aq) added to yield the precipitate?   0.001 L   0.01 L   0.10 L

Chemistry
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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An excess volume of 0.10 M BaCl2(aq) is mixed with 1.0 L of Na2SO4(aq) and forms 2.33 g of precipitate.

What is the net ionic equation for the reaction?

 

Ba2+(aq) + SO42–(aq) → BaSO4(s)
 

2 Na+(aq) 2 Cl–(aq)  →      2 NaCl(s)
 

2 Na+(aq) 2 Cl–(aq) + Ba2+(aq) +  SO42–(aq)

→ 2 NaCl(s) + BaSO4(s)

What is the minimum volume of BaCl2(aq) added to yield the precipitate?

 

0.001 L
 

0.01 L
 

0.10 L
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