An aqueous solution containing 9.61 g of lead(II) nitrate is added to an aqueous solution containing 6.27 g of potassium chloride. Enter the balanced chemical equation for this reaction. Be sure to include all physical states. balanced chemical equation: Pb(N0,),(aq) + 2KCI(aq) → PbCl,(s) + 2KNO;(aq) What is the limiting reactant? lead(II) nitrate potassium chloride

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An aqueous solution containing 9.61 g of lead(II) nitrate is added to an aqueous solution containing 6.27 g of
potassium chloride.
Enter the balanced chemical equation for this reaction. Be sure to include all physical states.
balanced chemical equation: Pb(NO,),(aq) + 2KCI(aq) → PBCI, (s) + 2KNO;(aq)
What is the limiting reactant?
lead(II) nitrate
potassium chloride
The percent yield for the reaction is 87.6%. How many grams of the precipitate are formed?
precipitate formed: 7.065
g
How many grams of the excess reactant remain?
excess reactant remaining:
0.0587
Incorrect
Transcribed Image Text:An aqueous solution containing 9.61 g of lead(II) nitrate is added to an aqueous solution containing 6.27 g of potassium chloride. Enter the balanced chemical equation for this reaction. Be sure to include all physical states. balanced chemical equation: Pb(NO,),(aq) + 2KCI(aq) → PBCI, (s) + 2KNO;(aq) What is the limiting reactant? lead(II) nitrate potassium chloride The percent yield for the reaction is 87.6%. How many grams of the precipitate are formed? precipitate formed: 7.065 g How many grams of the excess reactant remain? excess reactant remaining: 0.0587 Incorrect
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