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Chlorine can be prepared in the laboratory by the reaction of manganese dioxide with hydrochloric acid, HCl(aq), as described by the chemical equation MnO₂ (s) + 4 HCl(aq) → MnCl₂(aq) + 2H₂O(l) + Cl₂(g) How much MnO₂ (s) should be added to excess HCl(aq) to obtain 395 mL Cl₂(g) at 25 °C and 805 Torr? mass of MnO₂: 2

Chlorine can be prepared in the laboratory by the reaction of manganese dioxide with hydrochloric acid, HCl(aq), as described by the chemical equation MnO₂ (s) + 4 HCl(aq) → MnCl₂(aq) + 2H₂O(l) + Cl₂(g) How much MnO₂ (s) should be added to excess HCl(aq) to obtain 395 mL Cl₂(g) at 25 °C and 805 Torr? mass of MnO₂: 2

Chemistry
Chemistry
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ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
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Chlorine can be prepared in the laboratory by the reaction of manganese dioxide with hydrochloric acid, HCl(aq), as described by the chemical equation MnO₂ (s) + 4 HCl(aq) → MnCl₂(aq) + 2 H₂O(1) + Cl₂(g) How much MnO₂ (s) should be added to excess HCl(aq) to obtain 395 mL Cl₂(g) at 25 °C and 805 Torr? mass of MnO₂: g
Transcribed Image Text:Chlorine can be prepared in the laboratory by the reaction of manganese dioxide with hydrochloric acid, HCl(aq), as described by the chemical equation MnO₂ (s) + 4 HCl(aq) → MnCl₂(aq) + 2 H₂O(1) + Cl₂(g) How much MnO₂ (s) should be added to excess HCl(aq) to obtain 395 mL Cl₂(g) at 25 °C and 805 Torr? mass of MnO₂: g
Expert Solution
Step 1

In this reaction, 1 mole MnO2 react with 4 mole HCl to form 1 mole Cl2.

MnO2 react with excess HCl. so MnO2 is the limiting reactant.

1 atm = 760 torr

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