How many grams of sodium hydroxide will react with a solution containing 73.00 g HCI? Molar masses NaOH, 39.99 g/mol, HCI 36.45 g/mol. NaOH(aq) + HCl(aq) = NaCl(aq) + H2O(l)
How many grams of sodium hydroxide will react with a solution containing 73.00 g HCI? Molar masses NaOH, 39.99 g/mol, HCI 36.45 g/mol. NaOH(aq) + HCl(aq) = NaCl(aq) + H2O(l)
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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![**Question:**
How many grams of sodium hydroxide will react with a solution containing 73.00 g HCl? Molar masses NaOH, 39.99 g/mol, HCl 36.45 g/mol.
**Chemical Equation:**
\[ \text{NaOH}(aq) + \text{HCl}(aq) \rightarrow \text{NaCl}(aq) + \text{H}_2\text{O}(l) \]
**Explanation and Solution:**
1. **Understand the Chemical Equation:**
The balanced chemical reaction provided is:
\[ \text{NaOH}(aq) + \text{HCl}(aq) \rightarrow \text{NaCl}(aq) + \text{H}_2\text{O}(l) \]
This equation shows that one mole of sodium hydroxide (NaOH) reacts with one mole of hydrochloric acid (HCl) to produce one mole of sodium chloride (NaCl) and one mole of water (H2O).
2. **Calculate Moles of HCl:**
Given:
- Mass of HCl = 73.00 g
- Molar mass of HCl = 36.45 g/mol
Moles of HCl can be calculated using the formula:
\[ \text{Moles of HCl} = \frac{\text{Mass of HCl}}{\text{Molar mass of HCl}} \]
\[ \text{Moles of HCl} = \frac{73.00 \, \text{g}}{36.45 \, \text{g/mol}} \]
\[ \text{Moles of HCl} \approx 2.0027 \, \text{mol} \]
3. **Calculate Moles of NaOH:**
Since the reaction between NaOH and HCl is in a 1:1 molar ratio, the moles of NaOH required will be equal to the moles of HCl.
\[ \text{Moles of NaOH} = 2.0027 \, \text{mol} \]
Given:
- Molar mass of NaOH = 39.99 g/mol
4. **Calculate Mass of NaOH:**
The mass of NaOH required can be calculated using the formula:
\[ \text{Mass of](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F2cfae0b3-b761-48b0-bf7a-43df83f62bab%2Fd26061d7-b1f4-417f-af68-2da5f8df983c%2Flppoac_processed.jpeg&w=3840&q=75)
Transcribed Image Text:**Question:**
How many grams of sodium hydroxide will react with a solution containing 73.00 g HCl? Molar masses NaOH, 39.99 g/mol, HCl 36.45 g/mol.
**Chemical Equation:**
\[ \text{NaOH}(aq) + \text{HCl}(aq) \rightarrow \text{NaCl}(aq) + \text{H}_2\text{O}(l) \]
**Explanation and Solution:**
1. **Understand the Chemical Equation:**
The balanced chemical reaction provided is:
\[ \text{NaOH}(aq) + \text{HCl}(aq) \rightarrow \text{NaCl}(aq) + \text{H}_2\text{O}(l) \]
This equation shows that one mole of sodium hydroxide (NaOH) reacts with one mole of hydrochloric acid (HCl) to produce one mole of sodium chloride (NaCl) and one mole of water (H2O).
2. **Calculate Moles of HCl:**
Given:
- Mass of HCl = 73.00 g
- Molar mass of HCl = 36.45 g/mol
Moles of HCl can be calculated using the formula:
\[ \text{Moles of HCl} = \frac{\text{Mass of HCl}}{\text{Molar mass of HCl}} \]
\[ \text{Moles of HCl} = \frac{73.00 \, \text{g}}{36.45 \, \text{g/mol}} \]
\[ \text{Moles of HCl} \approx 2.0027 \, \text{mol} \]
3. **Calculate Moles of NaOH:**
Since the reaction between NaOH and HCl is in a 1:1 molar ratio, the moles of NaOH required will be equal to the moles of HCl.
\[ \text{Moles of NaOH} = 2.0027 \, \text{mol} \]
Given:
- Molar mass of NaOH = 39.99 g/mol
4. **Calculate Mass of NaOH:**
The mass of NaOH required can be calculated using the formula:
\[ \text{Mass of
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