What is the mass of solute, in grams, in 100. mL of a 1.179 x 10-³ M solution of Na3PO4? -3 Mass of solute = g 3- What are the molar concentrations of the Na+ and PO4³- ions? Molar concentration Na+ 3- Molar concentration PO4³ = 3 M
What is the mass of solute, in grams, in 100. mL of a 1.179 x 10-³ M solution of Na3PO4? -3 Mass of solute = g 3- What are the molar concentrations of the Na+ and PO4³- ions? Molar concentration Na+ 3- Molar concentration PO4³ = 3 M
Chemistry
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ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
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![### Determining the Mass of Solute and Molar Concentrations in a Na₃PO₄ Solution
**Problem Statement:**
We need to find out:
1. The mass of the solute (in grams) in 100. mL of a 1.179 × 10⁻³ M solution of Na₃PO₄.
2. The molar concentrations of the Na⁺ and PO₄³⁻ ions in this solution.
**Solution Steps:**
**1. Mass of Solute:**
To determine the mass of solute:
\[ \text{Mass of solute} = \_\_\_\_\_\_\_\_\_ \text{ g} \]
**2. Molar Concentrations of Ions:**
To determine the molar concentrations:
\[ \text{Molar concentration of } \text{Na}^+ = \_\_\_\_\_\_\_\_\_ \text{ M} \]
\[ \text{Molar concentration of } \text{PO}_4^{3-} = \_\_\_\_\_\_\_\_\_ \text{ M} \]
**Explanation of Calculations:**
**a. Mass of Solute:**
- Convert volume from mL to L: \[ 100 \text{ mL} = 0.100 \text{ L} \]
- Use the molarity formula to calculate moles of Na₃PO₄:
\[ \text{Moles} = \text{Molarity} \times \text{Volume (in L)} \]
\[ \text{Moles} = 1.179 \times 10^{-3} \text{ M} \times 0.100 \text{ L} \]
- Calculate the molar mass of Na₃PO₄ by adding the atomic masses:
- Na (Sodium) = 22.99 g/mol (3 atoms)
- P (Phosphorus) = 30.97 g/mol (1 atom)
- O (Oxygen) = 16.00 g/mol (4 atoms)
- Total molar mass = (3 \times 22.99) + (1 \times 30.97) + (4 \times 16) g/mol
- Find the mass of Na₃PO₄:
\[ \text{Mass} = (\text{M](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F7a354f1c-cdfd-41e5-a863-9a86a504af1c%2Fff282c55-fcf7-406b-bd1e-02c7fb0b4628%2Fom7wf_processed.png&w=3840&q=75)
Transcribed Image Text:### Determining the Mass of Solute and Molar Concentrations in a Na₃PO₄ Solution
**Problem Statement:**
We need to find out:
1. The mass of the solute (in grams) in 100. mL of a 1.179 × 10⁻³ M solution of Na₃PO₄.
2. The molar concentrations of the Na⁺ and PO₄³⁻ ions in this solution.
**Solution Steps:**
**1. Mass of Solute:**
To determine the mass of solute:
\[ \text{Mass of solute} = \_\_\_\_\_\_\_\_\_ \text{ g} \]
**2. Molar Concentrations of Ions:**
To determine the molar concentrations:
\[ \text{Molar concentration of } \text{Na}^+ = \_\_\_\_\_\_\_\_\_ \text{ M} \]
\[ \text{Molar concentration of } \text{PO}_4^{3-} = \_\_\_\_\_\_\_\_\_ \text{ M} \]
**Explanation of Calculations:**
**a. Mass of Solute:**
- Convert volume from mL to L: \[ 100 \text{ mL} = 0.100 \text{ L} \]
- Use the molarity formula to calculate moles of Na₃PO₄:
\[ \text{Moles} = \text{Molarity} \times \text{Volume (in L)} \]
\[ \text{Moles} = 1.179 \times 10^{-3} \text{ M} \times 0.100 \text{ L} \]
- Calculate the molar mass of Na₃PO₄ by adding the atomic masses:
- Na (Sodium) = 22.99 g/mol (3 atoms)
- P (Phosphorus) = 30.97 g/mol (1 atom)
- O (Oxygen) = 16.00 g/mol (4 atoms)
- Total molar mass = (3 \times 22.99) + (1 \times 30.97) + (4 \times 16) g/mol
- Find the mass of Na₃PO₄:
\[ \text{Mass} = (\text{M
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