When [Et] = 20 nM and [SAD] = 40 µM, the reaction velocity, V0, is 9.6µM s1. Calculate Km for the substrate SAD.
When [Et] = 20 nM and [SAD] = 40 µM, the reaction velocity, V0, is 9.6µM s1. Calculate Km for the substrate SAD.
Biochemistry
9th Edition
ISBN:9781319114671
Author:Lubert Stryer, Jeremy M. Berg, John L. Tymoczko, Gregory J. Gatto Jr.
Publisher:Lubert Stryer, Jeremy M. Berg, John L. Tymoczko, Gregory J. Gatto Jr.
Chapter1: Biochemistry: An Evolving Science
Section: Chapter Questions
Problem 1P
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could you elaborate more on the process of step 2? it isn't explained vey well
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An
enzyme
is discovered that catalyzes the chemical reaction A team of motivated researchers sets out to
study the enzyme, which they call
happyase. They find that the kcat for happyase is 600 s and carry out several additional experiments.
When [Et] = 20 nM and [SAD] = 40 µM, the reaction velocity, V0, is 9.6µM s. Calculate Km for the substrate
-
SAD.
SAD = HAPPY
Transcribed Image Text: SAD = HAPPY
Expert Solution
Step 1
Enzymes are the biomolecules which acts as catalysts for many biochemical reactions and increases the
rate of reaction by decreasing the activation energy required for the reaction.
Step 2
In the given question, the given enzymatic reaction that is catalyzed by enzyme Happyase is:
SAD = HAPPY
The given concentration of substrate [SAD] is 40 uM, and enzyme concentration is 20 nM. The Kcat for
the enzyme is 600 /sec. The rate of reaction (Vo) is 9.6 uM/sec. The Km can be calculated as follows:
Vтахутах
TE; ]
Vmax[S
Km + [S
Кcat 3D
— Кcat x| E, Vтах — 600 x 20 х 10-3 риM/secVmax
12 иМ/secVo
Step 3
Hence, the Km for the substrate SAD is 10 µM.](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fb922951d-2773-4842-822d-60d5ada7ed63%2F4d6f1788-b999-4d05-81fa-06eaa4d4433a%2Fh029ti_processed.jpeg&w=3840&q=75)
Transcribed Image Text:Get live help whenever you need from online tutors! Try bartleby tutor today >
Q SEARCH
& ASK AN EXPERT
A CHAT
Vx MATH SOLVER
An
enzyme
is discovered that catalyzes the chemical reaction A team of motivated researchers sets out to
study the enzyme, which they call
happyase. They find that the kcat for happyase is 600 s and carry out several additional experiments.
When [Et] = 20 nM and [SAD] = 40 µM, the reaction velocity, V0, is 9.6µM s. Calculate Km for the substrate
-
SAD.
SAD = HAPPY
Transcribed Image Text: SAD = HAPPY
Expert Solution
Step 1
Enzymes are the biomolecules which acts as catalysts for many biochemical reactions and increases the
rate of reaction by decreasing the activation energy required for the reaction.
Step 2
In the given question, the given enzymatic reaction that is catalyzed by enzyme Happyase is:
SAD = HAPPY
The given concentration of substrate [SAD] is 40 uM, and enzyme concentration is 20 nM. The Kcat for
the enzyme is 600 /sec. The rate of reaction (Vo) is 9.6 uM/sec. The Km can be calculated as follows:
Vтахутах
TE; ]
Vmax[S
Km + [S
Кcat 3D
— Кcat x| E, Vтах — 600 x 20 х 10-3 риM/secVmax
12 иМ/secVo
Step 3
Hence, the Km for the substrate SAD is 10 µM.
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