When dATP binds in the A site, it acts as an inhibitor. ATP also binds in this site, but with much lower affinity. How does the structure of the enzyme explain the differential binding of dATP and ATP in the A site
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When dATP binds in the A site, it acts as an inhibitor. ATP also binds in this site, but with much lower affinity. How does the structure of the enzyme explain the differential binding of dATP and ATP in the A site
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- “Caspase” describes the catalytic activity of this enzyme. What amino acyl residue participates in the catalytic mechanism? What substrate motif does caspase-8 recognize?The allosterically regulated enzyme ATCase binds aspartic acid as a substrate and acylates the α–amino group. Succinate acts as a competitiveinhibitor of ATCase because it binds the active site but can’t be acylated.The dependence of v0 on [aspartic acid] for ATCase is shown in panel (a)of the accompanying figure. Panel (b) shows the effect of increasing [succinate] on v0 when [Asp] is held at a low concentration (see thick vertical arrow in panel (a)). Note that in panel (b), v0 is not zero when [succinate] = 0 (see thin horizontal arrow). Explain the shape of the curve in panel (b). Why does v0 increase initially, before decreasing at higher [succinate]?In a particular enzyme,an alanine residue is located in a cleft where the substrate bonds.A mutation that changes this residue to glycine has little effect on activity,however another mutation ,which changes the alanine to a glutamate residue,leads to loss of activity.Provide a brief explanation for those observation
- n a particular enzyme, an alanine residue is located in a cleft where the substrate binds. A mutation that changes this residue to glycine has little effect on activity; however, another mutation, which changes the alanine to a glutamate residue, leads to a complete loss of activity. Provide a brief explanation for these observationYou have isolated a new protease that cleaves peptide bonds on the carboxyl side of Asp and Glu. Based on the enzyme's inactivation by DIPF, you suspect that it may utilize a mechanism similar to chymotrypsin. The difference in specificity might be explained by the absence of the S1 binding pocket. replacement of serine 195 with a positively charged residue. presence of a positively charged residue in the S1 binding pocket. presence of a negatively charged residue in the S1 binding pocket.In a particular enzyme, an alanine residue is located in a cleft where the substrate binds. A mutation that changes this residue to glycine has little effect on activity; however, another mutation, which changes the alanine to a glutamate residue, leads to a complete loss of activity. Provide a brief explanation for these observations. As a follow-up on the previous question, you have another enzyme that you suspect binds its substrate in a similar site as the enzyme you are studying above. Assuming you have access to techniques whereby you could synthesize mutant proteins, outline experimental steps you would use to help you determine whether the two proteins recognize substrate by similar structural features.
- A carboxypeptidase is a metalloenyme (its active site contains one or more metal ions essential for the function) that catalyzes the hydrolysis of the peptide bond of the terminal amino acid of a polypeptide chain (where the free carboxyl group occurs). The binding of an L-alanyl-L-tyrosine peptide substrate in the active site of the enzyme is represented in the scheme below: Glu Zn++ COO™ OH H3C CH₂ HC NH IO C H H Poche apolaire -H H O+N: C N H H H NH₂ Arg 145 Туг 248 NB: This scheme gives a planar representation of the spatial structure of the active site where indicated contacts (hatched lines) are supposed to occur in the 3D structure of the enzyme. 1- Describe the interactions that occur between the ligand and amino acid residues of the active site. 2- What would be the impact on the Km value if we replace L-alanyl-L-tyrosine by the following substrates: L-alanyl-L-phenylalanine; L-alanyl-L-aspartate; L-aspartyl-L- tyrosine.The steps of the chymotrypsin mechanisms are listed below (1-7). Put the steps of chymotrypsin mechanism in the correct order. Figure representing chymotrypsin mechanism is given for reference. a.The portion (N-terminal end) of original substrate with the new C terminus diffuses away b. Substrate binding c. His 57 catalyzes removal of H from Ser 195 hydroxyl; Ser 195’s nucleophilic O attacks carbonyl C of substrate; tetrahedral intermediate is formed d. Water binding; water is deprotonated by His 57; resulting OH nucleophilically attacks carbonyl of remaining substrate; tetrahedral intermediate is formed e. His 57 donates H to N of…Trypsin cleaves proteins on the carboxyl side of lysine. Trypsin inhibitor has a lysine residue, and binds to trypsin, yet it is not a substrate. Explain.
- UDP-glucuronosyltransferase enzymes bind the organic compound UDP-glucuronic acid (UDP-GA) in order to catalyse the transfer of a glucuronic acid group from UDP-GA to a drug molecule, releasing UDP from the active site as a product. UDP is then regenerated by the activity of another enzyme. What terms could be used to describe UDP-GA?Diisopropylphosphofluoridate (DIPF) inactivates chymotrypsin by covalently modifying serine 195. Which statement is true of DIPF's inhibitory mechanism? DIPF randomly modifies all serine residues on the protein, and if enough is added, the serine in the active site will eventually be modified. DIPF approaches serine 195 more closely than other substrates. DIPF looks like the substrate for chymotrypsin and binds in the active site as a competitive inhibitor. Serine 195 is in an environment that gives it a higher than normal reactivity with respect to DIPF.The diagram below shows an outline of the aminotransferase mechanism that skips the specific steps that show how electrons flow when a Schiff base is formed or is hydrolyzed. Using the mechanistic details given below A. Draw the mechanism for Enzyme- PLP Schiff base formation using pyridoxal and the lysine amine group using arrow to indicate electron flow. B.Draw the mechanism for hydrolysis of the Schiff base to form the a-keto acid, which is the reverse of the first reaction.