When calculating enthalpy of reaction values, we use the "products minus reactants" mathematical model. Which explanation of this model is most correct? A) The products are coming into existence, thus we use their enthalpy of formation. The reactants are ceasing to exist, thus we use the opposite of their enthalpy of formation. B) "Products minus reactants" is an equation, not a model, and thus tells us nothing about the reaction. C) We model the chemical reaction as taking reactants and turning them into products. The exact steps don't matter as long as it comes to the product eventually. That is why we use "products minus reactants." D) We model the reaction as taking reactant molecules and dispersing them in to pieces (the opposite of the formation reaction of the reactants) and taking those pieces and condensing them down into products (the same as the formation reaction for those products.) Thus we take the negative of the enthalpy of formation for the reactants and add it to the enthalpy of formation of the products. This is the equivaent of "products minus reactants."
When calculating enthalpy of reaction values, we use the "products minus reactants" mathematical model. Which explanation of this model is most correct? A) The products are coming into existence, thus we use their enthalpy of formation. The reactants are ceasing to exist, thus we use the opposite of their enthalpy of formation. B) "Products minus reactants" is an equation, not a model, and thus tells us nothing about the reaction. C) We model the chemical reaction as taking reactants and turning them into products. The exact steps don't matter as long as it comes to the product eventually. That is why we use "products minus reactants." D) We model the reaction as taking reactant molecules and dispersing them in to pieces (the opposite of the formation reaction of the reactants) and taking those pieces and condensing them down into products (the same as the formation reaction for those products.) Thus we take the negative of the enthalpy of formation for the reactants and add it to the enthalpy of formation of the products. This is the equivaent of "products minus reactants."
Chemistry & Chemical Reactivity
10th Edition
ISBN:9781337399074
Author:John C. Kotz, Paul M. Treichel, John Townsend, David Treichel
Publisher:John C. Kotz, Paul M. Treichel, John Townsend, David Treichel
Chapter5: Principles Of Chemical Reactivity: Energy And Chemical Reactions
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Problem 62PS: An important step in the production of sulfuric acid is the oxidation of SO2 to SO3. SO2(g) + O2(g)...
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The term exergonic is derived from the Greek word in which ‘ergon’ means work and exergonic means ‘work outside’. Exergonic reactions releases work energy. Exergonic reactions are different from exothermic reactions, the one that releases only heat energy during the course of the reaction. So, exothermic reaction is one type of exergonic reaction. Exergonic reaction releases work energy in different forms like heat, light or sound. For example, a glow stick releases light making that an exergonic reaction and not an exothermic reaction since no heat is released. Even endothermic reactions at very high temperature are exergonic.
Question
When calculating enthalpy of reaction values, we use the "products minus reactants" mathematical model. Which explanation of this model is most correct?
A) The products are coming into existence, thus we use their enthalpy of formation. The reactants are ceasing to exist, thus we use the opposite of their enthalpy of formation.
B) "Products minus reactants" is an equation, not a model, and thus tells us nothing about the reaction.
C) We model the chemical reaction as taking reactants and turning them into products. The exact steps don't matter as long as it comes to the product eventually. That is why we use "products minus reactants."
D) We model the reaction as taking reactant molecules and dispersing them in to pieces (the opposite of the formation reaction of the reactants) and taking those pieces and condensing them down into products (the same as the formation reaction for those products.) Thus we take the negative of the enthalpy of formation for the reactants and add it to the enthalpy of formation of the products. This is the equivaent of "products minus reactants."
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