When a metal at a higher temperature is transferred to water at a lower temperature, heat the value of the is inevitably lost to the calorimeter. How does this heat loss change calculated specific heat compared to the actual specific heat?

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**Question 3:**

When a metal at a higher temperature is transferred to water at a lower temperature, heat is inevitably lost to the calorimeter. How does this heat loss change the value of the calculated specific heat compared to the actual specific heat?

**Explanation:**

In a typical calorimetry experiment, a metal is heated and then placed in water to determine its specific heat. If some of the heat is lost to the calorimeter and surroundings, this loss will result in an inaccurate measurement of the specific heat. The observed specific heat value will be lower than the actual specific heat because part of the heat that should have increased the water temperature was instead lost.
Transcribed Image Text:**Question 3:** When a metal at a higher temperature is transferred to water at a lower temperature, heat is inevitably lost to the calorimeter. How does this heat loss change the value of the calculated specific heat compared to the actual specific heat? **Explanation:** In a typical calorimetry experiment, a metal is heated and then placed in water to determine its specific heat. If some of the heat is lost to the calorimeter and surroundings, this loss will result in an inaccurate measurement of the specific heat. The observed specific heat value will be lower than the actual specific heat because part of the heat that should have increased the water temperature was instead lost.
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