When a round bar material with diameter of 37.5 mm, length of 2.4 m, Young's modulus of 110 GN/m? and shear modulus of 42 GN/m? is stretched for 2.5 mm, its Bulk modulus will be nearly (a) 104 GN/m2 (c) 84 GN/m2 (b) 96 GN/m? (d) 76 GN/m2
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- The results of a tensile test are shown in Table 1.5.2. The test was performed on a metal specimen with a circular cross section. The diameter was 3 8 inch and the gage length (The length over which the elongation is measured) was 2 inches. a. Use the data in Table 1.5.2 to produce a table of stress and strain values. b. Plot the stress-strain data and draw a best-fit curve. c. Compute the, modulus of elasticity from the initial slope of the curve. d. Estimate the yield stress.When a round bar material with diameter of 37.5mm, length of 2.4 m, Young's modulus of 110 GN/m² and shear modulus of 42 GN/m² is stretched for 2.5 mm, its bulk modulus will be nearly (a) 104 GN/m² (c) 84 GN/m² (b) 96 GN/m² (d) 76 GN/m²When a round bar material with diameter of 37.5 mm, length of 2.4 m, Young's modulus of 110 GN/m² and shear modulus of 42 GN/m² is stretched for 2.5 mm, its Bulk modulus will be nearly (a) 104 GN/m² (c) 84 GN/m² (b) 96 GN/m² (d) 76 GN/m²
- Q- A cylindrical piece of steel, with a diameter of 60mm and length 100 mm, is subjected to an axial compressive force of 40,000 kg. If bulk modulus is 1.7 x 106 kg/cm² and poisson's ratio is 0.25 than the change in volume of the cylindrical piece is1) A cylindrical titanium bar, an initial length of 10 inches and a diameter of 0.167 ft, is subjected to loading. After loading, the initial length of the 10-inch bar is reduced to 9.998 inches. Since the young's modulus of the titanium bar is 16.5*106 psi, find the load (kip) acting on the bar. Indicate whether the loading is tension or compression.The composite material is fastened to their junction at rigid plate B and attached to rigid fixed supports at both ends subjected to two loads of 12k positioned symmetrically at B. Determine the stresses and their corresponding behavior for each material. Use 2 decimal places in every solved value. 亚 А 12k 12k 1 ft Steel Est = 29 x 10° psi Ast = 1.03 in? B Aluminum 2 ft Eal = 10 × 106 psi Aal = 8.92 in² C
- A metal specimen with 20 mm diameter and 100 mm gauge length is loadedelastically with 5 kN and elongates 0.8 mm. Its diameter under this load is 19.95 mm. Calculate:a) the Bulk Modulus, Kb) the Shear Modulus, GA RECTANGULAR ALUMINUM BLOCK IS 40mm LONG IN THE Y DIRECTION, 20mm WIDE IN THE Z DIRECTION AND 25mm THICK IN THE X DIRECTION. IT IS SUBJECTED TO A TRIAXIAL LOADING CONSISTING OF A UNIFORMLY DISTRIBUTED FORCE OF Px=3 (COMPRESSION), Py=6 (TENSION) AND Pz=9 (COMPRESSION) IN THE X, Y AND Z DIRECTIONS RESPECTIVELY. IF THE POISSON’S RATIO = 1/4 & E = 70 GPa, DETERMINE THE STRAINS IN THE X, Y AND Z DIRECTIONS. ALSO DETRMINE A SINGLE DISTRIBUTED FORCE IN THE Y DIRECTION THE WOULD PRODUCE THE SAME X DEFORMATION AS THE ORIGINAL.10:59 0.63 a. Y l KB/S VPN tutorial 1.pdf Axlal 1oads are applied to uie compounu rou inal is composeu of an aluminum segment rigidly connected between steel and bronze segments. (a) What is the stress in each material given that P = 10 kN? (b) Find the largest safe value of P if the working stresses are 120 MPa for steel, 68 MPa for aluminum, and 110 MPa for 2. Aluminum Steel A=300 mm² Bronze A=400 mm? A=600 mm² 2P 4P 3m -5m 4m bronze. Answer: a) 0one = 50 MPa; ouminum = 33.3 MPa; oel = 100 MPa ; b) P = 12KN A circular aluminum tube of length L = 400 mm is loaded in compression by axial forces P at the ends. The ou inside diameters are 60 mm and 50 mm, respectively. A strain gage is placed on the outside of the bar to measur strains in the longitudinal direction (axial direction). (a) If the measured compressive strain is ɛ = 550×10-6 , what is the shortening ô of the bar? (b) If the compressive stress in the bar is intended to be 40 MPa, what should be the load P? Answer: a) 8 = 0.22…
- A uniform concrete slab is to be attached to two rods whose lowers ends are initially at the same level. What is the required area, in mm², of aluminum rod so that slab will remain level after it is attached to the rods? 4 m Aluminum E = 72 GPa Steel A= 96 mm < E = 200 GPa 4 m 3 m- 0.50 mWhat is the maximum diameter of aggregate considering the clear spacing of the reinforcements in mm? 160mm slab Slab=10mm 130mm beam 700mm 17.25cm 500mm 4 Obeam=25mm D =?The composite bar consists of a 25-mm-diameter A-36 steel segment AB and 60-mm-diameter red brass C83400 end segments DA and CB. (Figure 1) Figure -250 mm- D A 500 mm 75 kN 75 kN 100 KN 100 KN B 1 of 1 > 250 mm- C Part A Determine the average normal stress in segment DA due to the applied load. Express your answer to three significant figures and include the appropriate units. ODA = Submit Part B JAB = O Submit HÅ Value Request Answer Determine the average normal stress in segment AB due to the applied load. Express your answer to three significant figures and include the appropriate units. μA Value C Request Answer Units ? Units ?