When a piece of paper is held with one face perpendicular to a uniform electric field the flux through it is 427 N.m2/C. When the paper is turned such that the angle between the surface of the paper and the electric field is 48°, find the flux through the paper. Express your answer in units of  N.m2/C with one decimal place. Note that your answer should be positive.

Q: When a piece of cardboard is held with its face perpendicular to a uniform electric field, the flux…

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Q: Item 6 A charged object with electric charge q produces an electric field. The SI unit for electric…

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Q: We have an electric flux of magnitude 141 Nm2/ C passing through a flat horizontal surface with an…

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Q: A point charge q = +5 µC is at the center of a sphere of radius 0.6 m. (a) Find the surface area of…

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Q: A flat square with sides 18 cm is placed in a uniform electric field of magnitude 5784 N/C. What is…

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Q: The drawing shows an edge-on view of two planar surfaces that intersect and are mutually…

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Q: Charges q1 and q2 are placed on the y-axis at y = 0 and y = 26 m, respectively. If q1 = -44.2 pC and…

A: Using Gauss law of electrostatics The net flux through a closed surface is given by Where Qenc =…

Q: 7. The drawing shows an edge-on view of two planar surfaces that intersect and are mutually…

A: Draw the schematic diagram of the system.

Q: The drawing shows an edge-on view of two planar surfaces that intersect and are mutually…

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Q: An electric field of 5.4 N/C passes through an area of 3.4 cm2. Calculate the flux in units of 10^-4…

A: Given data:  Electric field (E) = 5.4 N/C Area (A) = 3.4 cm2 = 3.4×10-4 m2  Angle between electric…

Q: R 1. Suppose that a charged rod of uniform charge density is formed into a semi- circle of radius R.…

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Q: 15.7c   Consider a closed triangular box resting within a horizontal electric field of magnitude E =…

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Q: A flat surface of area 3.30 m2 is rotated in a uniform electric field of magnitude E = 7.00  105…

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Q: The surface shown is a square and has a side length of 11.0 cm. The electric field acting on this…

A: It is given that

Q: The drawing shows an edge-on view of two planar surfaces that intersect and are mutually…

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Q: A rectangular surface extends from x = 0 to x = 50.0 cm and from y = 0 to y = 42.0 cm in the xy…

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Q: A point charge produces an electric flux of +305 N-m2 /C through a gaussian sphere of radius 14.5 cm…

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Q: Which expression describes electric flux through an infinitesimal area dA where is the angle between…

A: Given the electric flux is \phi and infinitesimal area is given by dA. Consider a surface with a…

Q: (4000 + 3000 k) N/C. What is its electric flux through a circular area of Consider the uniform…

A: Given data: The electric field, E→=4000 j^+3000 k^ N/C The radius, r=1.43 m

Q: Consider the uniform electric field E = (2.5 j + 2.5 k) × 103 N/C. a) Calculate the electric flux…

A: Given: The uniform electric filed E is (2.5 j⏜ + 2.5 k⏜)×103 N/C. The radius of the circular area in…

Q: A flat sheet of paper of area 0.355 m2 is oriented so that the normal to the sheet is at an angle of…

A: Given: Area of the sheet, A = 0.355 m2 The angle between the normal to the sheet and the electric…

Q: A Gaussian surface has the form of a tetrahedron, a four-sided object where all four sides are…

A: We will answer the question using Gauss's law. The details are as follows.

Q: Assume the magnitude of the electric field on each face of the cube of edge L = 1.11 m in the figure…

A: The flux on each surface can be calculated as Where E is the electric field on each face and A is…

Q: The drawing shows an edge-on view of two planar surfaces that intersect and are mutually…

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Q: Consider an electric field=33x ₁ - 81y ₁. The coordinates x and y are measured in meters and the…

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Q: A flat piece of cardboard with area 84.0 cm2 is immersed in a uniform electric field of strength…

A: Given : Electric Field (E) = 5.2 x 103 N/C Area (A) = 84 cm2 = 0.0084 m2 Angle between E and A is 76…

Q: The figure below shows a closed cylinder with cross-sectional area A 3.20 m². The constant electric…

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A: Given Electric charges, Q1 = 0 C, Q2 = 4 C, and Q3 = -5 C.We know that flux by Gauss's Law is given…

Q: Assume the magnitude of the electric field on each face of the cube of edge L = 1.10 m in the figure…

A: Given that:- Edge length of cube=L=1.1m

Electric Charges and Fields

One of the fundamental properties is the electromagnetic property. Charge cannot be destroyed by any process and this contributes formally to the law of charge conservation.