The figure below shows a closed cylinder with cross-sectional area A 3.20 m². The constant electric field E has magnitude 1.85 x 10³ N/C and is directed vertically upward, perpendicular to the cylinder's top and bottom surfaces so that no field lines pass through the curved surface. Calculate the electric flux (in (N-m²)/C) through the cylinder's top and bottom surfaces. HINT (a) top surface (b) bottom surface N-m² N-m² (c) Determine the amount of charge (in C) inside the cylinder.

The figure below shows a closed cylinder with cross-sectional area A 3.20 m². The constant electric field E has magnitude 1.85 x 10³ N/C and is directed vertically upward, perpendicular to the cylinder's top and bottom surfaces so that no field lines pass through the curved surface. Calculate the electric flux (in (N-m²)/C) through the cylinder's top and bottom surfaces. HINT (a) top surface (b) bottom surface N-m² N-m² (c) Determine the amount of charge (in C) inside the cylinder.

College Physics

11th Edition

ISBN:9781305952300

Author:Raymond A. Serway, Chris Vuille

Publisher:Raymond A. Serway, Chris Vuille

Chapter1: Units, Trigonometry. And Vectors

Section: Chapter Questions

Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...

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Electric Charges and Fields

One of the fundamental properties is the electromagnetic property. Charge cannot be destroyed by any process and this contributes formally to the law of charge conservation.

Question

The figure below shows a closed cylinder with cross-sectional area A = 3.20 m².
The constant electric field E has magnitude 1.85 x 10 N/C and is directed vertically upward, perpendicular to the cylinder's top and bottom surfaces so that no field lines pass
through the curved surface. Calculate the electric flux (in (Nm²/C) through the cylinder's top and bottom surfaces.
WINTE
(a) top surface
(b) bottom surface
N-m²
N-m²
(c) Determine the amount of charge (in C) inside the cylinder.

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