Two conducting hollow spheres share a common center. The inner sphere has the radius a = 5.0 cm and charge +3.2x10-6 C. The outer sphere has the radius b = 32 cm and charge -4.0x10-6 C. What is the electric field (in N/C) at a point P, r = 20 cm from the center of the spheres? %3D P
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- 2C. Two horizontal squares metal plates, with a side of 10 cm, are placed horizontally and parallel one on top of the other at a distance of 1 cm. They acquire opposite charges of equal absolute value price, so that there is a gap between them to have a homogeneous electric field of 2x103 N/C down direction. A particle of mass 2x10-16 Kg with a positive charge of 1x106 C leaves the center of of negative bottom plate with an initial velocity of measure 1x105 m/s at an angle of 37° with the horizontal. Where will it hit, relative to the starting point? (Consider whether gravity can be ignored.) E ++ + + ++++ + FThe electric flux through the surface shown in the figure is 17 Nm^2/C. What is the electric field strength? Express your answer to two significant figures and include the appropriate unitsA shere of radius R = 0.35 m has a volume charge distribution described by: ρ(r) = ρ0 (1− r/R) for r ≤ R, where ρ0 = 18.5 μC/m3. a. What is the total charge on the sphere? b. What is the strength of the electric field produced by the charge distribution at a distance 0.21 m from the center of the sphere? c. What is the strength of the electric field produced by the charge distribution at a distance 0.4025 m from the center of the sphere? d. Graph the electric field as a function of r between r = 0 and r =0.4025 m.
- A spherical shell of radius 1.40 m contains a single charged particle with q = 38.0 nC at its center. (a) What is the total electric flux through the surface of the shell? N. m²/c (b) What is the total electric flux through any hemispherical portion of the shell's surface? N. m²/cA uniformly charged disk of radius R=25 cm carries a total charge of Q=2 μC. R P 1 Find the magnitude of the electric field E created by the disk at the point P located at distance 40 cm from the center of the disk. E = [N/C] 2. What is the direction of the electric field E created by the disk at point P. Direction: 3. Write the expression of the electric filed E created by the disk at point P. Ē =< [N/C] 4. Find the magnitude of the electric field E created by the disk at the point P located at distance 8 m from theNeeds Complete typed solution with 100 % accuracy.
- A uniform electric field of magnitude 2.7 x 104 N/C is perpendicular to a square sheet with sides 2.5 m long. What is the electric flux through the sheet? Hint Electric flux is PE Question Help: Message instructor Submit Question N.m²/C.07 A closed surface with dimensions a = b = 0.400 m and c = 0.800 m is located as shown in the figure below. The left edge of the closed surface is located at position x = a. The electric field throughout the region is non- uniform and given by E. = [k (xy?) ↑ + k (x²y)j] N/C, where x,y are in meters, k =5.00 m3 1) Use ( E · îdA to calculate the flux through each surface. (should be SIX answers)4. A point charge q=+15.0µC is located at the origin. A hollow spherical conductor of inner radius a=0.0500 m and outer radius b=0.0950 m is concentric with the point charge, and has a net charge Q= -20.0µC. Using Gauss's law, derive the equation for the magnitude of the electric field as a function of r. a
- A hollow thin conducting shell has a radius of 1.00x10-6m. The electric field at a distance of 3.00x10-6m is measured to be 1250 N/C directed toward the center of the shell. Find a.The charge on the shell. b.The electric field inside the hollow conducting shell (r < 1.00x10-6m).A point charge is located at the origin. Centered along the x axis is a cylindrical closed surface of radius 10 cm with one end surface located at x = 2 m and the other end surface located at x = 2.5 m. If the magnitude of the electric flux through the surface at x = 2 m is 4 N . m2 /C, what is the magnitude of the electric flux through the surface at x = 2.5 m? Select one: a. 1.8 N . m2 /C b. 2.56 N . m2 /C c. 1.0 N . m2 /C d. 4.0 N . m2 /C e. 5.0 N . m2 /C