For a given surface, the electric flux, PE, is proportional to the number of field lines through the surface. For a uniform electric field, the maximum electric flux is equal to the product of electric field at the surface and the surface area (i.e., EA). The electric flux is defined to be positive when the electric field E has a component in the same direction as the area vector A and is negative when the electric field has a component in the direction opposite to the area vector. C. Sketch vectors A and E such that the electric flux is: Positive Negative Zero

For a given surface, the electric flux, PE, is proportional to the number of field lines through the surface. For a uniform electric field, the maximum electric flux is equal to the product of electric field at the surface and the surface area (i.e., EA). The electric flux is defined to be positive when the electric field E has a component in the same direction as the area vector A and is negative when the electric field has a component in the direction opposite to the area vector. C. Sketch vectors A and E such that the electric flux is: Positive Negative Zero

College Physics

11th Edition

ISBN:9781305952300

Author:Raymond A. Serway, Chris Vuille

Publisher:Raymond A. Serway, Chris Vuille

Chapter1: Units, Trigonometry. And Vectors

Section: Chapter Questions

Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...

See similar textbooks

Related questions

Q: Part (a) What is the change in electric potential, in volts, from point (0, 0) to point (x₁, 0)? V…

Q: A uniform circular ring has charge Q and radius r. A uniformly charged disk also has charge Q and…

A: The electric field due to the ring is now for the ring at a distance of Z= r and Radius R = r,Then…

Q: We have an electric flux of magnitude 141 Nm2/ C passing through a flat horizontal surface with an…

Q: flat surface of area 3.60 m2 is rotated in a uniform electric field of magnitude E = 5.65 105 N/C.…

A: Given, E = 5.65×10⁵ N/C A = 3.60 m²

Q: In the figure a butterfly net is in a uniform electric field of magnitude E = 5.4 mN/C. The rim, a…

A: If the electric field E is uniform, the electric flux (ΦE) passing through a surface of area A is:…

Q: 10. Which of the following best describes diffraction? a. The bending of a wave as it crosses the…

A: Diffraction : Diffraction refers to various phenomena that occur when a wave encounters an obstacle…

Q: A square surface of side length L and parallel to the y-z plane is situated in an electric field…

A: The objective of the question is to find the total electric flux through a square surface in an…

Q: A charge of -36 µC is distributed uniformly throughout a spherical volume of radius 26.0 cm.…

Q: A flat square with sides 18 cm is placed in a uniform electric field of magnitude 5784 N/C. What is…

Q: A flat surface of area 2.70 m2 is rotated in a uniform electric field of magnitude E = 5.85 x 105…

Q: A closed surface with dimensions a = b= 0.208 m and c = 0.3328 m is located as in the figure. The…

A: Putting values of α and β in expression of electric field,I obtain E=5+6x2 Total Electric flux is…

Q: A sphere of radius R carries a volume charge density given by ρ(r)=αr where r is the distance to the…

A: The objective of the question is to find the total charge carried by the sphere. The volume charge…

Q: A positive test charge is placed in a uniform electric field region, with magnitude E = 1 x 103 N/C.…

A: Given: The magnitude of the electric field in the region = 1×103 N/C The magnitude of positive test…

Q: der the uniform electric field E = (4.0ĵ + 3.0k) × 10³ N/C. What is the electric agnitude through a…

Q: Calculate the electric field in N/C which extends radially from an infinitely long straight wire…

Q: A flat surface of area 3.30 m2 is rotated in a uniform electric field of magnitude E = 7.00 105…

Q: Which expression describes electric flux through an infinitesimal area dA where is the angle between…

A: Given the electric flux is \phi and infinitesimal area is given by dA. Consider a surface with a…

Q: If the electric flux through a sphere is 10.0 Nm^2/C, what is the electric flux through a sphere of…

A: Given: The electric flux through a sphere is ϕ1=10.0 Nm2/C,

Q: A line of charge of length L is lying along the x axis with its left end at the origin. The linear…

A: Electric field due to a line of charge having linear charge density E=14πε∘∫λdlr2…

Q: Consider the uniform electric field E = (2.5 j + 2.5 k) × 103 N/C. a) Calculate the electric flux…

A: Given: The uniform electric filed E is (2.5 j⏜ + 2.5 k⏜)×103 N/C. The radius of the circular area in…

Q: A closed surface is constructed in the space between two large parallel metal plates, where there is…

A: Magnitude of electric field,Area increment ,Then,The electric flow through any surface is denoted…

Q: A uniform electric field with a magnitude of 1.25x105 N/C passes through a rectangle with sides of…

A: Given Data: The uniform electric field is E = 1.25 x 105 N/C. The sides of the rectangle are L =…

Q: he electric flux (Φ) that passes through this surface

A: we know electric flux ϕ = E·A =EAcosθ where θ= angle between electric field and area vector A = area…

Q: What is the electric field at the center of a sphere of radius R whose volume is uniformly filled…

A: Given charge Q is uniformly distributed over the volume of sphere having radius R. Therefore charge…

Q: An electric field is given by the following vector: E = 9.48 x 104 N/m, at a direction of 111° W of…

A: Step 1: DIVIDE THE ELECTRIC FIELD IN COMPONENT OF Y AND X Step 2: PUT THE VALUE OF SIN(111) AND…

Concept explainers

Electric Charges and Fields

One of the fundamental properties is the electromagnetic property. Charge cannot be destroyed by any process and this contributes formally to the law of charge conservation.

Question

For a given surface, the electric flux, PE, is proportional to the number of field lines through
the surface. For a uniform electric field, the maximum electric flux is equal to the product of
electric field at the surface and the surface area (i.e., EA). The electric flux is defined to be
positive when the electric field E has a component in the same direction as the area vector A and
is negative when the electric field has a component in the direction opposite to the area vector.
C. Sketch vectors A and Ē such that the electric flux is:
Positive
Negative
Zero

Expert Solution

This question has been solved!

Explore an expertly crafted, step-by-step solution for a thorough understanding of key concepts.

This is a popular solution!

SEE SOLUTION Check out a sample Q&A here

Step 1: Introduce the formula of electric flux

VIEW

Step 2: Determine when flux is positive

VIEW

Step 3: Determine when flux is negative

VIEW

Step 4: Determine when flux is zero

VIEW

Solution

VIEW

Trending now

This is a popular solution!

Step by step

Solved in 5 steps with 4 images

SEE SOLUTION Check out a sample Q&A here

Knowledge Booster

Learn more about

Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, physics and related others by exploring similar questions and additional content below.

Similar questions

Consider a thin, spherical shell of radius 16.0 cm with a total charge of 29.8 µC distributed uniformly on its surface. (a) Find the electric field 10.0 cm from the center of the charge distribution. magnitude Is the point 10 cm from the center inside or outside the sphere? MN/C direction (b) Find the electric field 25.0 cm from the center of the charge distribution. magnitude MN/C direction
A constant electric field of magnitude Eo points in the direction of the positive z-axis. What is the net electric flux through a cube, given the area (at z=0 and z>0) normal to the electric fields is A? Eo O 0 O 2*Eo*A +Eo*A -Eo*A
Question 5: Consider the following situation: A ring of radius R is centered on the x axis a distance l from the origin. The ring has a uniform electric charge density per unit length d, d > 0. Show that the electric filed at a location on the x axis, a distance l from the origin comes out to be Ē = 2nkeAlR (?+ R?}3/2 Hint: You will need to set up an integration for this problem.
A charge distribution creates the following electric field throughout all space: E(r, 0, q) = (3/r) (r hat) + 2 sin cos sin 0(theta hat) + sin cos p (phi hat). Given this electric field, calculate the charge density at location (r, 0, p) = (ab.c).
Consider a cylindrically symmetric distribution of charge. It consists of a tube of charge of radius 0.6 m with a linear charge density of 284.8 x 10-12 C/m that is surrounded by a second tube of charge of radius 4.1 m with linear charge density -188.5 x 10-12 C/m. Calculate the magnitude of the electric field, in N/C, 1.7 m away from the axis of the distribution. Use ?0ε0 = 8.85 x 10-12 F/m. (Please answer to the fourth decimal place - i.e 14.3225)
Plot a graph of the electric field as a function of distance r from the centre of the sphere, and write an expression for the electric field at the surface of the sphere (r=R)
A box with a cross-section of 1m x 1m x 1m is surrounding a plan of charge. The uniform electric field is equal to 8 N/C. The total electric flux through this box is
An electric field 7 N/C is passing through a region of area 2.1 m² in the xy-plane. If the electric field makes an angle of 56° with respect to the area vector perpendicular to the region, calculate the electric flux magnitude (in N-m²/C) through the region.
Problem 1: Part (a) Express the magnitude of the electric field between the two plates, E, in terms of the charge q on one plate, its area A, and ε0. E = ______ Part (b) Express the electric flux ΦE, in terms of q and ε0. ΦE = ______ Part (c) Express the derivative of ΦE with respect of time t in terms of I and ε0. dΦE/dt = ______ Part (d) What is the displacement current which is passing through the capacitor in amps? ID = ______ A
A vertical wall (6.3 mx 3.3 m) in a house faces due east. A uniform electric field has a magnitude of 210 N/C. This field is parallel to the ground and points 34° north of east. What is the electric flux through the wall? Number: Units
A uniform electric field of magnitude 35,000 N/C makes an angle of 47° with a plane surface of area 0.0153 m². What is the electric flux through this surface?
A circular surface is inclined about 40° when it is in an electric field of 10000 N/C. The radius of the circular surface is 9.0 cm and the angle is made with the area vector and electric field. Determine the electrical flow on the surface.