An electric field 7 N/C is passing through a region of area 2.1 m² in the xy-plane. If the electric field makes an angle of 56° with respect to the area vector perpendicular to the region, calculate the electric flux magnitude (in N-m²/C) through the region.
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A: The formula for the electric flux in terms of the electric field is:
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Q: C
A: GivenE=(3.0 j+7.0 k)×103 N/C
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- A square surface of area 2.3 cm2 is in a space of uniform electric field of magnitude 1800 NC. The amount of flux through it depends on how the square is oriented relative to the direction of the electric field. Find the electric flux through the square, when the normal to it makes the following angles with the electric field. Note that these angles can also be given as 180°+θ. (a) 30° (b) 90° (c) 0°A uniform electric field of magnitude 5.7 x 104 N/C is at an angle of 10° to a square sheet with sides 5.5 m long. What is the electric flux through the sheet? Hint Electric flux is E N.m²/C.A uniform electric field of magnitude 5.5 x 104 N/C passes through the plane of a square sheet with sides 9.0 m long. Calculate the flux (in Nm²/C) through the sheet if the plane of the sheet is at an angle of 30° to the field. Find the flux for both directions of the unit normal to the sheet. unit normal with component parallel to electric field Nm²/C unit normal with component antiparallel to electric field Nm²/c Additional Materials
- A uniform electric field of magnitude 3.6×104N/C is at an angle of 80° to a square sheet with sides 8.5 m long. What is the electric flux through the sheet?An electric field of magnitude 3.42 kN/C is applied along the x axis. Calculate the electric flux through a rectangular plane 0.350 m wide and 0.700 m long if the following conditions are true. (a) The plane is parallel to the yz plane. N · m2/C(b) The plane is parallel to the xy plane. N · m2/C(c) The plane contains the y axis, and its normal makes an angle of 37.6° with the x axis. N · m2/CA uniform electric field 98 x 103 N/C passes through a circular surface of radius 12.2 cm as shown in the diagram. Find the magnitude of electric flux (in N m2 C-1) passing through that surface if a=36 degrees.
- A uniform electric field with a magnitude of 1.25x105 N/C passes through a rectangle with sides of 2.50 m and 5.0 m . If the electric flux through the rectangle is 6.6x105 Nm2/C , the vector normal to the rectangular surface ?A right conical frustrum is placed in a uniform electric field that is parallel to the y axis, as shown. The magnitude of the electric field is 43 N/C. The electric flux measured through the top surface is 2240 N-m?/C, and the electric flux measured through the bottom surface is 4480 N-m²/C. What is the electric flux through the side of the frustrum?