A flat surface with area vector equal to × = (1.40 î – 1.10 ĵ + 1.60 k) m² is immersed in a uniform electric field given by E = (1800.0î + 1200.0ĵ + 1600.0 k) N/C. The electric flux through this surface is i N m²/C.
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- A uniform electric field of magnitude E = 38.5 N/C makes and angle of θ = 67.3° relative to a line normal to a surface with area A = 3.01 m2. What is the electric flux (Φ) that passes through this surface? Your answer should be in N·m2/CA disk of radius 132mm is oriented with its normal unit vector at 30 degrees to a uniform electric field E of magnitude 2.23x10^3 N/C. (a) what is the electric flux through the disk? (b) What is the flux through the disk if n is parallel to EAn insulating solid sphere of radius R = 6.0cm has a total positive charge Q uniformly distributed throughout its volume. The electric flux through a spherical Gaussian surface of radius r = 3.0cm is 2.26x105N.m2/C. How much charge (in units of μC) is enclosed by the Gaussian surface of radius r =3.0cm? What is the magnitude ( in units of 106N/C) of the E-field at the Gaussian surface of part (1)? What is the magnitude (in units of 106N/C) of the E-field at surface of the sphere?
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