A charge of -36 µC is distributed uniformly throughout a spherical volume of radius 26.0 cm. Determine the electric field (in N/C) due to this charge at the following distances from the center of the sphere. (Enter the radial component of the electric field.) (a) 9.0 cm E : ]× NC)t (b) 18.0 cm (c) 34.0 cm E = ( N/CP

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Chapter1: Units, Trigonometry. And Vectors
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A charge of \(-36 \, \mu \text{C}\) is distributed uniformly throughout a spherical volume of radius \(26.0 \, \text{cm}\). Determine the electric field (in N/C) due to this charge at the following distances from the center of the sphere. (Enter the radial component of the electric field.)

(a) \(9.0 \, \text{cm}\)  
\[ \vec{E} = \text{(}\_\_\_\_\_\_\_\_\_\_\text{N/C\ˆ)\ } \]

(b) \(18.0 \, \text{cm}\)  
\[ \vec{E} = \text{(}\_\_\_\_\_\_\_\_\_\_\text{N/C\ˆ)\ } \]

(c) \(34.0 \, \text{cm}\)  
\[ \vec{E} = \text{(}\_\_\_\_\_\_\_\_\_\_\text{N/C\ˆ)\ } \]
Transcribed Image Text:A charge of \(-36 \, \mu \text{C}\) is distributed uniformly throughout a spherical volume of radius \(26.0 \, \text{cm}\). Determine the electric field (in N/C) due to this charge at the following distances from the center of the sphere. (Enter the radial component of the electric field.) (a) \(9.0 \, \text{cm}\) \[ \vec{E} = \text{(}\_\_\_\_\_\_\_\_\_\_\text{N/C\ˆ)\ } \] (b) \(18.0 \, \text{cm}\) \[ \vec{E} = \text{(}\_\_\_\_\_\_\_\_\_\_\text{N/C\ˆ)\ } \] (c) \(34.0 \, \text{cm}\) \[ \vec{E} = \text{(}\_\_\_\_\_\_\_\_\_\_\text{N/C\ˆ)\ } \]
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