7. The drawing shows an edge-on view of two planar surfaces that intersect and are mutually perpendicular. Surface (1)has an area of 1.50 m², while surface (2) has an area of 4.00 m². The electric field in the drawing is uniform and has amagnitude of 200 N/C. Find the magnitude of the electric flux through surface (2) if the angle 0 made between theelectric field with surface (2) is 37.0⁰.(9J$$un J$$ (9J$$ (9588 (9JEssf60 ssf60 ssf60 ss/60 ss160s:60 ssf60 ssfoSurface 2f60 ssfossTӨSurface 1ssf60 ssf60 ssf60sf60 sssfen ssf60sf60 ssf60 ssf60 ssf60 ssf6050 ssf60 ssf60 ssf60 ssf6

Draw the schematic diagram of the system.

7. The drawing shows an edge-on view of two planar surfaces that intersect and are mutually perpendicular. Surface (1) has an area of 1.50 m², while surface (2) has an area of 4.00 m². The electric field in the drawing is uniform and has a magnitude of 200 N/C. Find the magnitude of the electric flux through electric field with surface (2) is 37.0⁰. Nm²/C Essi 60 ss160sface (2) if the angle 8 made between the f60 ssf60 ssf60 ssf60 E f60 ssf60 ssf60 ssf60 ssf60 ssf60 Surface 2 Surface 1 ssf60 ssf60 ssf60 f60160 ssf60 ssf60 ssf60 ss ssf60 ssf60 ssf60 ssf

7. The drawing shows an edge-on view of two planar surfaces that intersect and are mutually perpendicular. Surface (1) has an area of 1.50 m², while surface (2) has an area of 4.00 m². The electric field in the drawing is uniform and has a magnitude of 200 N/C. Find the magnitude of the electric flux through electric field with surface (2) is 37.0⁰. Nm²/C Essi 60 ss160sface (2) if the angle 8 made between the f60 ssf60 ssf60 ssf60 E f60 ssf60 ssf60 ssf60 ssf60 ssf60 Surface 2 Surface 1 ssf60 ssf60 ssf60 f60160 ssf60 ssf60 ssf60 ss ssf60 ssf60 ssf60 ssf

College Physics

11th Edition

ISBN:9781305952300

Author:Raymond A. Serway, Chris Vuille

Publisher:Raymond A. Serway, Chris Vuille

Chapter1: Units, Trigonometry. And Vectors

Section: Chapter Questions

Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...

See similar textbooks

Similar questions

The electric field at a distance of 0.154 m from the surface of an insulating solid sphere of radius 0.385 m is 1970 N/C. Assuming that the charge on the sphere is uniformly distributed, a) what is the charge density within it? b) Calculate the electric field inside the sphere at a distance of 0.150 m from the center.
A vertical electric field of magnitude 2.00 x 104 N/C exists above the Earth's surface on a day when a thunderstorm is brewing. A car with a rectangular size of 6.00 m by 3.00 m is traveling along a dry gravel roadway sloping downward at 10.0°. Determine the electric flux through the bottom of the car.
The electric flux through the surface shown in the figure (Figure 1)is 30 Nm²/C. You may want to review (Pages 664 - 668). Š Figure 60° 10 cm x 10 cm 1 of 1 Part A What is the electric field strength? Express your answer to two significant figures and include the appropriate units. E = Submit 0 ΜΑ Value Provide Feedback Request Answer Ć Units w ?
Problem 3. Charge Metal Rod. An isolated very long metallic rod with a uniform circular cross section of radius 0.55 mm has a constant charge per unit length of 2.25 x 10-8 C/m. Find the electric field magnitudes at distances (a) 0.25 mm and (b) 0.75 mm, from the longitudinal axis of the rod.
A circular surface with a radius of 0.062 m is exposed to a uniform electric field of magnitude 1.58 × 104 N/C. The electric flux through the surface is 68 N·m2/C. What is the angle between the direction of the electric field and the normal to the surface?
9. The drawing shows an edge-on view of two planar surfaces that intersect and are mutually perpendicular. Surface (1) has an area of 2.50 m², while surface (2) has an area of 2.70 m2. The electric field in the drawing is uniform and has a magnitude of 220 N/C. Find the magnitude of the electric flux through surface (1) if the angle 0 made between the electric field with surface (2) is 32.0°. Nm2/C Surface 1 19.0of19 0of19 00f19 oof19 0of Surface 2 of19 0of19 o 9 00f19 oof1
A 39.0-cm-diameter circular loop is rotated in a uniform electric field until the position of maximum electric flux is found. The flux in this position is measured to be 5.42 x 105 Nm²/C. What is the magnitude of the electric field? MN/C Need Help? Read It Master it
The figure below shows a uniform electric field of magnitude E = 420 N/C making an angle of o = 66.5° with a flat surface of area A = 3.20 m2. What is the magnitude of the electric flux through this surface (in N · m2/C)? E N. m2/c
A vertical wall (6.3 mx 3.3 m) in a house faces due east. A uniform electric field has a magnitude of 210 N/C. This field is parallel to the ground and points 34° north of east. What is the electric flux through the wall? Number: Units
Calculate the absolute value of the electric flux for the following situations (In all case provide your answer in N m2/C): a. A constant electric field of magnitude 300 N/C at a 30 degrees angle with respect to the flat rectangular surface shown in the Figure above. b. A uniform electric field E = (70 i + 90 k) N/C through a 4 cm ×5 cm in the x-y plane. c. A uniform electric field E = (−350 i + 350 j + 350 k) N/C through a disk of radius 3 cm in the x-z plane.
An electric flux of 18.35 Nm2/C passes through a flat surface that is perpendicular to a constant electric field of strength 11.5 N/C. What is the area of the surface?
A point charge is located at the origin. Centered along the x axis is a cylindrical closed surface of radius 10 cm with one end surface located at x = 2 m and the other end surface located at x = 2.5 m. If the magnitude of the electric flux through the surface at x = 2 m is 4 N . m2 /C, what is the magnitude of the electric flux through the surface at x = 2.5 m? Select one: a. 1.8 N . m2 /C b. 2.56 N . m2 /C c. 1.0 N . m2 /C d. 4.0 N . m2 /C e. 5.0 N . m2 /C