A circular surface with a radius of 0.071 m is exposed to a uniform electric field of magnitude 1.47 x 104 N/C. The electric flux through the surface is 64 N-m²/C. What is the angle between the direction of the electric field and the normal to the surface?

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A circular surface with a radius of 0.071 m is exposed to a uniform electric field of magnitude 1.47 x 104 N/C. The electric flux through
the surface is 64 N-m2/C. What is the angle between the direction of the electric field and the normal to the surface?
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Transcribed Image Text:A circular surface with a radius of 0.071 m is exposed to a uniform electric field of magnitude 1.47 x 104 N/C. The electric flux through the surface is 64 N-m2/C. What is the angle between the direction of the electric field and the normal to the surface? Number i eTextbook and Media Units
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text Radius of circular surface end text space left parenthesis R right parenthesis space equals space 0.071 space m space
text Area of circular surface end text space left parenthesis A right parenthesis space equals space straight pi left parenthesis straight R right parenthesis squared space equals space straight pi cross times left parenthesis 0.071 right parenthesis squared space
equals space 0.015829 space straight m squared
text Electric field strength end text space left parenthesis straight E right parenthesis thin space equals 1.47 cross times 10 to the power of 4 space straight N over straight C
equals space 14700 space straight N over straight C
text Electric flux through the surface end text space left parenthesis empty set right parenthesis space equals space 64 space fraction numerator straight N. straight m squared over denominator straight C end fraction


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