When a brass rod of diameter 2 mm is subjected to a tension of Sx10 N, the diameter changes by 3.6x104 cm. Calculate the Poisson's ratio for brass given that the Elastic modulus for the brass is 9x100 N/m and thelongitudinal strain for the brass rod is1.96x103useful equation: Poissons ratio = Lateral strain / Longitudinal strainO 0.63O 031O 1.11O 0,92

Answered: Image /qna-images/answer/3c8105ba-24cd-4d56-b1fd-8177b801e71d.jpg

When a brass rod of diameter 2 mm is subjected to a tension of Sx10 N, the diameter changes by 3.6x104 cm. Calculate the Poisson's ratio for brass given that the Elastic modulus for the brass is 9x1010 N/m and the longitudinal stralin for the brass rod ist.96x103 useful equation: Poissons ratio = Lateral strain / Longitudinal strain O 0.63 O 031 1.11 O 0.92

When a brass rod of diameter 2 mm is subjected to a tension of Sx10 N, the diameter changes by 3.6x104 cm. Calculate the Poisson's ratio for brass given that the Elastic modulus for the brass is 9x1010 N/m and the longitudinal stralin for the brass rod ist.96x103 useful equation: Poissons ratio = Lateral strain / Longitudinal strain O 0.63 O 031 1.11 O 0.92

Elements Of Electromagnetics

7th Edition

ISBN:9780190698614

Author:Sadiku, Matthew N. O.

Publisher:Sadiku, Matthew N. O.

ChapterMA: Math Assessment

Section: Chapter Questions

Problem 1.1MA

See similar textbooks

Related questions

Q: c) A solid homogeneous truss tie-rod has a diameter of 9.52 mm and an original length of 1.75 m…

A: Given Data The daimeter of truss tie rod is:d=9.52 mm The length is:l=1.75 m The stress experienced…

Q: The diameter (d) of a solid rod (i.e., with a circular cross-section) is 16 mm and is made from a…

Q: A circular rod of diameter 20mm and 500mm long is subjected to a tensile force 50kN. The modulus…

Q: The weight is suspended from steel and aluminum wires, each having the same initial length of 3 m…

A: According to the given data WireArea(mm2)allowable stress(GPa)Modulus of…

Q: A copper wire 3m long and 1mm^2 in cross-section is fixed at one end and a weight of 10 kg is…

Q: An aluminum bar has length L = 5 ft and diameter d = 1.25 in. %D The stress-strain curve for the…

A: Data given- L = 5 ft = 5×12 = 60 in d = 1.25 in E = 10 × 106 psi P = 39 ksi

Q: A thin metal alloy plate is loaded by biaxial stress (2 directions) given by 8000 psi in the x…

Q: A wire of length L = 25 m and diameter d = 1.6 mm is stretched by a tensile force of P = 660 N. The…

Q: A straight length of copper steam pipe 450mm long connects two components. Find the stress in the…

A: According to the given data E=103Gpa L=450mm α=1.7x10-5/°C ∆T=140°C δ=0.8mm We need to find Stress…

Q: P solid, see Fig below. The outer diameter of the hollow and solid sections is 6 cm and the inner A…

A: Given: The outer diameter of the solid and hollow section: →Do=6 Cm=0.06 m The inner diameter of the…

Q: A steel (E=30x106 psi) rod 10m long and 5cm in diameter is subjected to a compressive force of…

Concept explainers

Thermal Properties of Materials

In mechanical engineering, the thermal property is represented as the physical quantity that is relevant to the application of heat. The thermal properties are evaluated by variations in any specific material due to low heat or high heat. The quantities that influence the thermal property of the materials are mass, density, temperature, and many others.

Question

100%

When a brass rod of diameter 2 mm is subjected to a tension of Sx10 N, the diameter changes by 3.6x104 cm. Calculate the Poisson's ratio for brass given that the Elastic modulus for the brass is 9x100 N/m and the
longitudinal strain for the brass rod is1.96x103
useful equation: Poissons ratio = Lateral strain / Longitudinal strain
O 0.63
O 031
O 1.11
O 0,92

Expert Solution

This question has been solved!

Explore an expertly crafted, step-by-step solution for a thorough understanding of key concepts.

This is a popular solution!

SEE SOLUTION Check out a sample Q&A here

Step 1

VIEW

Step 2

VIEW

Trending now

This is a popular solution!

Step by step

Solved in 2 steps with 2 images

SEE SOLUTION Check out a sample Q&A here

Knowledge Booster

Types of Properties of Engineering Materials

Learn more about

Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, mechanical-engineering and related others by exploring similar questions and additional content below.

Similar questions

Problem F2 stress (ksi) 130 120 110 100 90 80 70 60 50 40 30 20 10 0 0.000 0.025 0.050 0.075 0.100 0.125 0.150 0.175 strain (in/in) Above you will find the experimental stress-strain diagram of 1045 steel. Calculate the permanent set if a cylindrical specimen with a diameter of 2 in is loaded to the ultimate stress and then unloaded. Provide your answer in units of in/in with 3 significant figures after the decimal. The elastic modulus of 1045 steel is 29,000 ksi.
A tube has 25mm outside diameter and an axial tensile load of 40 kN. If the strain on the tube is limited to 0.1% and density of 7800kg/m^3, what is the maximum internal diameter of the tube in mm?
Need Help Pls
A rectangular block is 7 cm long in the x-direction, 5 cm in the y-direction, and 9 cm long in the z-direction. The block is subjected to a triaxial loading of three uniformly distributed forces as follows: 15 kN in the x- direction, 21 kN in the y-direction, and 18 kN in the z-direction. Calculate the strain in the direction y if Poisson's ratio v = 0.30 and having a modulus of elasticity of E = 150 GPa. y 7 cm 9 cm 21 kN 15 kN 5 cm 18 kN
(d) Define Modulus of Resilience 2. Draw the stress-strain diagram for a typical ductile material and locate the salient points onit 3. A bar of 25 mm diameter is tested in tension. It is observed that when a load of 60 kN is applied, the measured over a gauge length of 200 mm is 0.12 mm and contraction in diameter is 0.0045 mm. Find Poissa 4. A circular rod of diameter 16 mm and 500 mm long is subjected to a tensile force 40 kN. The modulus of e steel may be taken as 200 kN/mm?. Find the elongation and strainin the bar due to applied load. 5. Define (a) Resilience (b) Proof resilience PART -B structions: Part B consists of 3 Units. Answer any one full question from each unit. Each questioncarries 8 marks and may have su 1. A steel circular bar has three segments as shown in the fig. Determine the total elongation ofthe bar. Take E = 210 GPa. 300 kNI 330 kN 30 mm 50KN 15 mm 20 mm 80 kN A + 150 mm 200 mm 250 mm B. D (OR)
The diameter (d) of a solid rod (i.e., with a circular cross-section) is 16 mm and is made from a homogeneous material. The length (L) of the rod is 1.75 m and Young’s Modulus for the material (E) is 250 GPa. When the rod is placed under tension it experiences deformation and a stress (?) of 650 MPa. Calculate the following:(1) Strain energy (U) to 2 decimal places in Joules.(2) Strain energy per unit volume (U/V) in J/m3(3) The change in length ∆L to 2 decimal places in mm.(4) The strain (?) due to deformation to 2 significant figures. (show all work)
MECH OF DEFORM BODIES
A solid homogeneous truss tie-rod has a diameter of 9.52 mm and an original length of 1.75 m experiences a stress of 600 MPa when placed under tension. If the material used for the truss tie-rod has a Young's Modulus, E, of 5.8 x 1011 N/m?, calculate: (i) the tie-rod's extension in millimetres (mm); (ii) the strain energy (U) in Joules; and (ii) the strain energy per unit volume (U/V) in Joules per cubic metre (m³). Give your answers to two decimal places.
A steel bar 50 mm wide, 12mm thick and 300 mm long is subjected to an axial pull of 84 kN. Find the changes in the length, width, thickness and the volume of the bar. Take E = 200 GPa and Poisson's ratio= 0.32 δt = 0.0027mm (decrease), δV = 45.36mm³ (increase)]
I need a quick solution within 15 minutes Ton
An elastomeric bearing pad consisting of two steel plates bonded to a chloroprene elastomer is subjected to a shear force V during a static load- ing test . The pad has dimensions a = 125 mm and b = 240 mm, and the elastomer has thickness 50 mm When the force V equals 12 kN, the top plate is found to have displaced laterally 8.0 mm with respect to aleThe bottom plate.What is the shear modulus of elasticity G of the chloroprene ?
A rubber ball is inflated to a pressure of 60KPa. At that pressure, the diameter of the ball is 230mm and the wall thickness is 1.2mm. The rubber has a modulus of elasticity of E = 3.5MPa and Poisson’s ratio of 0.45. (a)Compute the maximum tensile stress. (b)If the allowable tensile stress of the rubber ball wall is 2.5MPa, compute the internal pressure the rubber ball could be inflated.