Solve asap An aluminum bar has length L = 5 ft and diameter d = 1.25 in.%D%3DThe stress-strain curve for the aluminum is shown in Fig. 1-13of Section 1.3. The initial straight-line part of the curve has aslope (modulus of elasticity) of 10 X 106 psi. The bar is loadedby tensile forces P = 39 k and then unloaded.What is thepermanent s t of the bar?deformationLoadingElasticrecoveryResidualstrain(b)FIG. 1-18 Stress-strain diagramsillustrating (a) elastic behavior,and (b) partially elastic behaviorFIG. 1-19 Reloading of a material andraising of the elastic and proportionallimitso (ksi)403020100 0.05 0.10 0.15 0.20 0.25FIG. 1-13 Typical stress-strain diagramfor an aluminum alloyBnpeorunLoadingBospeoUnloading

Data given- L = 5 ft = 5×12 = 60 in d = 1.25 in E = 10 × 106 psi P = 39 ksi

An aluminum bar has length L = 5 ft and diameter d = 1.25 in. %D The stress-strain curve for the aluminum is shown in Fig. 1-13 of Section 1.3. The initial straight-line part of the curve has a slope (modulus of elasticity) of 10 X 106 psi. The bar is loaded by tensile forces P = 39 k and then unloaded. What is the permanent s t of the bar? deformation

An aluminum bar has length L = 5 ft and diameter d = 1.25 in. %D The stress-strain curve for the aluminum is shown in Fig. 1-13 of Section 1.3. The initial straight-line part of the curve has a slope (modulus of elasticity) of 10 X 106 psi. The bar is loaded by tensile forces P = 39 k and then unloaded. What is the permanent s t of the bar? deformation

Elements Of Electromagnetics

7th Edition

ISBN:9780190698614

Author:Sadiku, Matthew N. O.

Publisher:Sadiku, Matthew N. O.

ChapterMA: Math Assessment

Section: Chapter Questions

Problem 1.1MA

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