When 0.0801 mol of an unknown hydrocarbon is burned in a bomb calorimeter, the calorimeter increases in temperature by 2.19°C. If the heat capacity of the bomb calorimeter is 1.229 kJ/°C, what is the heat of combustion for the unknown hydrocarbon?

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Chapter1: Chemical Foundations
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**Question 14 of 35: Calorimetry Problem**

When 0.0801 mol of an unknown hydrocarbon is burned in a bomb calorimeter, the calorimeter increases in temperature by 2.19°C. If the heat capacity of the bomb calorimeter is 1.229 kJ/°C, what is the heat of combustion for the unknown hydrocarbon?

**Calculation Interface:**

The interface provides a numeric keypad for inputting values in kJ/mol. It includes buttons for numbers 0-9, decimal point, positive/negative sign, and scientific notation (x10). A clear button (C) is also available to remove entered values.

**Instructions:**

To calculate the heat of combustion:

1. Use the formula: 
   \[
   \text{Heat of combustion} = \frac{\text{Heat absorbed by calorimeter}}{\text{moles of substance}}
   \]
   
2. Calculate the heat absorbed by the calorimeter:
   \[
   \text{Heat absorbed} = \text{Temperature change} \times \text{Heat capacity}
   \]
   \[
   \text{Heat absorbed} = 2.19°C \times 1.229 \text{kJ/°C}
   \]

3. Use the heat absorbed value in the combustion formula above.

**Further Resources:**

You can tap for additional resources to understand the concept of calorimetry and the principles behind combustion reactions.
Transcribed Image Text:**Question 14 of 35: Calorimetry Problem** When 0.0801 mol of an unknown hydrocarbon is burned in a bomb calorimeter, the calorimeter increases in temperature by 2.19°C. If the heat capacity of the bomb calorimeter is 1.229 kJ/°C, what is the heat of combustion for the unknown hydrocarbon? **Calculation Interface:** The interface provides a numeric keypad for inputting values in kJ/mol. It includes buttons for numbers 0-9, decimal point, positive/negative sign, and scientific notation (x10). A clear button (C) is also available to remove entered values. **Instructions:** To calculate the heat of combustion: 1. Use the formula: \[ \text{Heat of combustion} = \frac{\text{Heat absorbed by calorimeter}}{\text{moles of substance}} \] 2. Calculate the heat absorbed by the calorimeter: \[ \text{Heat absorbed} = \text{Temperature change} \times \text{Heat capacity} \] \[ \text{Heat absorbed} = 2.19°C \times 1.229 \text{kJ/°C} \] 3. Use the heat absorbed value in the combustion formula above. **Further Resources:** You can tap for additional resources to understand the concept of calorimetry and the principles behind combustion reactions.
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