When 0.0801 mol of an unknown hydrocarbon is burned in a bomb calorimeter, the calorimeter increases in temperature by 2.19°C. If the heat capacity of the bomb calorimeter is 1.229 kJ/°C, what is the heat of combustion for the unknown hydrocarbon?
Thermochemistry
Thermochemistry can be considered as a branch of thermodynamics that deals with the connections between warmth, work, and various types of energy, formed because of different synthetic and actual cycles. Thermochemistry describes the energy changes that occur as a result of reactions or chemical changes in a substance.
Exergonic Reaction
The term exergonic is derived from the Greek word in which ‘ergon’ means work and exergonic means ‘work outside’. Exergonic reactions releases work energy. Exergonic reactions are different from exothermic reactions, the one that releases only heat energy during the course of the reaction. So, exothermic reaction is one type of exergonic reaction. Exergonic reaction releases work energy in different forms like heat, light or sound. For example, a glow stick releases light making that an exergonic reaction and not an exothermic reaction since no heat is released. Even endothermic reactions at very high temperature are exergonic.
![**Question 14 of 35: Calorimetry Problem**
When 0.0801 mol of an unknown hydrocarbon is burned in a bomb calorimeter, the calorimeter increases in temperature by 2.19°C. If the heat capacity of the bomb calorimeter is 1.229 kJ/°C, what is the heat of combustion for the unknown hydrocarbon?
**Calculation Interface:**
The interface provides a numeric keypad for inputting values in kJ/mol. It includes buttons for numbers 0-9, decimal point, positive/negative sign, and scientific notation (x10). A clear button (C) is also available to remove entered values.
**Instructions:**
To calculate the heat of combustion:
1. Use the formula:
\[
\text{Heat of combustion} = \frac{\text{Heat absorbed by calorimeter}}{\text{moles of substance}}
\]
2. Calculate the heat absorbed by the calorimeter:
\[
\text{Heat absorbed} = \text{Temperature change} \times \text{Heat capacity}
\]
\[
\text{Heat absorbed} = 2.19°C \times 1.229 \text{kJ/°C}
\]
3. Use the heat absorbed value in the combustion formula above.
**Further Resources:**
You can tap for additional resources to understand the concept of calorimetry and the principles behind combustion reactions.](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fceafadd1-9c75-4be0-aae5-882235578510%2F6ec5ec5a-0e36-435f-b8d9-ca110f12a843%2F70tlq5_processed.png&w=3840&q=75)
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