What potential difference is needed to accelerate the following particles from rest to 0.05c, where c is the speed of light? a) a particle with a charge 6e and a mass 7u? V b) a particle with a charge 94e and a mass 240u? V
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A: A parallel-plate capacitor is charged to V = 5000 V.A proton is fired into the center of the…
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A: Given : Distance (d) = 2.10 m Initial speed = 0 Final speed (vf) = 1.33 x 105 m/s Mass of proton…
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A: charge on each proton (q) = 1.6×10-19 C distance of closest approach (d) = 8×10-14 m
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Q: 5:59 5GE ll 55% 017 (part 1 of 2) A proton is accelerated from rest through a potential difference…
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A: Given:-Applied accelerating voltage : Vapplied = 30kV = 30000VLet K be the kinetic energy of the…
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Q: Q.2. A charge q1 = 3.22 µC is at a distance d = 1.33 m from a second charge q2 = -4.87 µC. 71 3.22pc…
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Q: An electron is to be accelerated in a uniform electric field having a strength of 2x106 V/m.…
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Q: The uniform electric field between two parallel plates of opposite and separate loads of 40 mm has…
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Q: An electron is accelerated from rest through a potential difference of 1.2 kV. Find the change in…
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A: Given that: Initial speed: vi=178260.0 m/scharge of proton: q=+1.6×10-19 C (known)mass of proton,…
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Q: In a television picture tube, electrons strike the screen after being accelerated from rest through…
A: The electrostatic potential energy of electron is converted into the kinetic energyTherefore, we can…
Q: 002 (part 1 of 2) A proton is accelerated through a potential difference of 4.4 x 10°. How much…
A: part 1 According to the work-energy theorem, the kinetic energy acquired by the proton will be equal…
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A: Given data:Uniform electric field, E=2×106 V/mDistance, d=0.4 m
Q: An object with a charge of 17.4 C and a mass of 0.39 kg is travelling horizontally with a speed of…
A: An object with a charge of and massis traveling horizontally at a speed into the charged plates.The…
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A: Given data: Initial velocity (Vi) = 0 m/s Potential difference (ΔV) = 500 V Charge on proton q = e…
Q: hegative plates of a parallel plate capacitor is d = 10 mm, each plate has a length L = 10 cm, see…
A: Given,the space between capacitors d=10 mm=0.01 m length of each plate L=10 cm=0.1 m Electric field…
Q: Review Multiple-Concept Example 4 to see the concepts that are pertinent here. In a television…
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Q: An evacuated tube uses an accelerating voltage of 30 kV to accelerate electrons to hit a copper…
A: Step 1: Step 2: Step 3: Step 4:
Q: An unknown particle is measured to have a negative charge and a speed of 2.24 < 108 m/s. Its…
A: We have to determine the particle by finding its mass.
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- An Alpha particle ( a Helium nucleus with a +2e charge) enters a parallel plate arrangement through a hole in the positive plate held at +5.0V and is accelerated towards the negative plate held at -5.0V. a) What is speed of the Alpha particle when it reaches the negative plate? (Assume its initial velocity is zero) b) How fast is it moving when it is at the center of the gap between the plates? Mass of Alpha Particle: m = 6.645 × 10-27kg a Elementary charge: e = 1.602× 10-19C= A point charge q₁ 9.1 µC is held fixed at 0.42 μC and a mass origin. A second point charge 2 3.2 x 104 kg is placed on the x-axis, 0.96 m from the origin. The second point charge is released at rest. What is its speed when it is 0.24 m from the origin? =please help
- An electron is to be accelerated in a uniform electric field having a strength of 2.106 (a) What energy in keV is given to the electron if it is accelerated through 0.45 m? AKE = keV m (b) Over what distance (in km) would it have to be accelerated to increase its energy by 45 GeV? d = ✔km Hint: How is potential energy, PE, gained by an electron related to the uniform electric field? How is the potential difference, V, related to the uniform electric field?What is the speed of an electron after being accelerated from rest through a 2.5×107 V potential difference? Express your answer as a fraction of cc.A proton is fired from very far away directly at a fixed particle with charge q = 1.60 ✕ 10−18 C. If the initial speed of the proton is 1.7 ✕ 105 m/s, what is its distance of closest approach to the fixed particle? The mass of a proton is 1.67 ✕ 10−27 kg.
- If electrons have kinetic energy of 2000 eV, find (a) their speed, (b) the time needed to traverse a distance of 5 cm between plates that our horizontal, and (c) the vertical component of their velocity after passing between the plates if the electric field is 3.33 x 10^3 V/m.An electron is to be accelerated in a uniform electric field having a strength of 1.90 106 V/m. (a) What energy in keV is given to the electron if it is accelerated through 0.810 m?_________ keV(b) Over what distance would it have to be accelerated to increase its energy by 50.0 GeV (as in the Stanford Linear Accelerator, which is actually smaller than this)? ________kmTwo parallel plates are separated by 2.50cm and connected to a 120V battery. a)What is the magnitude of the existing field between the plates? b)How much work is done on a proton to move it from the positive plate to the negative plate if it starts from rest and it moves horizontally? c)How much is the electric force acting in the proton? d)How much is its acceleration? e)With what speed does it reach the negative plate?
- A positive charge of 4.20 μC is fixed in place. From a distance of 4.20 cm a particle of mass 6.20 g and charge +3.00 μC is fired with an initial speed of 62.0 m/s directly toward the fixed charge. How close to the fixed charge does the particle get before it comes to rest and starts traveling away? (in cm)Two parallel plates are separated ?=0.00375 mx=0.00375 m and have a potential difference of ?=1610 V.V=1610 V. A small ball with mass ?=9.10×10−12 kgm=9.10×10−12 kg is placed between the two plates and remains motionless and floating between the plates. From the overall charge on the ball, determine the number of electrons ?ene the ball has gained or lost. The acceleration due to gravity is ?=9.81 m/s2,g=9.81 m/s2, and the elementary unit of charge is ?=1.60×10−19 C.An electron is to be accelerated over a distance 3.84m in a uniform electric field having a strength of 6.04x 10 V m What distance is required to give the electron a kinetic energy of 6.74GeV (in m)? M 31