Q.2. A charge q1 = 3.22 µC is at a distance d = 1.33 m from a second charge q2 = -4.87 µC. 71 3.22pc 92 A * -4.87 PC d- 1.33m ➜ Find the electric field and potential at a point A between the two charges that is d/3 from q1.

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Chapter1: Units, Trigonometry. And Vectors
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-1.6×10 19 x 100V =
W = - APE
^ KE = -1
1.6 x 10
-d-
-1.6
rodigin by
J
(doso siq E) :19
Q.2. A charge q1 = 3.22 µC is at a distance d = 1.33 m from a second charge q2 = -4.87 μC.
91 3.22pC
92
A
ilguoid sus car
siprit esw 100
-4.87 μC
k
1.33m101
Find the electric field and potential at a point A between the two charges that is d/3 from 91.
OR
6.0.0
ra V Girar. // in all cand bot
C₁ = 3.12 µF, C2 = 19.7 uF.)
2.3. Find the total capacitance of the combination of capacitors shown in the figure below.
Transcribed Image Text:-1.6×10 19 x 100V = W = - APE ^ KE = -1 1.6 x 10 -d- -1.6 rodigin by J (doso siq E) :19 Q.2. A charge q1 = 3.22 µC is at a distance d = 1.33 m from a second charge q2 = -4.87 μC. 91 3.22pC 92 A ilguoid sus car siprit esw 100 -4.87 μC k 1.33m101 Find the electric field and potential at a point A between the two charges that is d/3 from 91. OR 6.0.0 ra V Girar. // in all cand bot C₁ = 3.12 µF, C2 = 19.7 uF.) 2.3. Find the total capacitance of the combination of capacitors shown in the figure below.
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