Answered: A positive charge q1 = 3.24 nC is… | bartleby

Related questions

Question

A positive charge q1 = 3.24 nC is located at a point on thex-axis a distance 49.3 cm from the origin of an xy coordinate
system. Another negative charge q2 = -6.10 nC is at a point on the y-axis a distance 52.4 cm from the origin. What is the
potential value (in volts) due to these two charges at the origin?
Enter your answer with at least three significant figures and no units.

Expert Solution

Trending now

This is a popular solution!

Step by step

Solved in 3 steps with 3 images

SEE SOLUTION Check out a sample Q&A here

Blurred answer

Similar questions

Oppositely charged parallel plates are separated by 6.30 mm. A potential difference of 600 V exists between the plates. (a) What is the magnitude of the electric field between the plates? N/C (b) What is the magnitude of the force on an electron between the plates? N (c) How much work must be done on the electron to move it to the negative plate if it is initially positioned 2.80 mm from the positive plate?
A point charge q₁ = 3.90 nC is placed at the origin, and a second point charge q2 = -2.95 nC is placed on the x-axis at x = +20.0 cm. A third point charge q3 = 2.10 nC is to be placed on the x-axis between q₁ and 92. (Take as zero the potential energy of the three charges when they are infinitely far apart.) ▼ Part A What is the potential energy of the system of the three charges if q3 is placed at x = + 11.0 cm ? V—| ΑΣΦ U= 9.5 107 8 Submit Part B X Incorrect; Try Again ● x = 7.62 cm Previous Answers Request Answer ✔ Correct Where should q3 be placed between q₁ and q2 to make the potential energy of the system equal to zero? Previous Answers ? J
The plates of a parallel-plate capacitor are 3.22 mm apart, and each has an area of 9.92 cm². Each plate carries a charge of magnitude 4.50x10-8 C. The plates are in vacuum. ▼ What is the capacitance? Express your answer with the appropriate units. C = Submit Part B PHÅ V = Value Request Answer What is the potential difference between the plates? Express your answer with the appropriate units. 98 Value C μᾶ Units Units ? ?
D only please
A small object with a mass of 4.92 mg carries a charge of 33.4 nC and is suspended by a thread between the vertical plates of a parallel-plate capacitor. The plates are separated by 5.79 cm. If the thread makes an angle of 12.3° with the vertical, what is the potential difference in volts between the plates? Round your answer to 1 decimal place. Add your answer
A parallel-plate capacitor consists of two plates, each with an area of 25 cm2 separated by 3.0 mm . The charge on the capacitor is 4.8 nC . A proton is released from rest next to the positive plate. How long does it take for the proton to reach the negative plate? Express your answer with the appropriate units.
A small positive test charge of 0.02C is situated 1.5m away from a positive charge of 1C and 4.2m away from a second positive charge of 14C. What is the total potential energy of the test charge. The coulomb constant K = 9E9. Give your answer in GigaJoules (GJ)
In the rectangle in Figure, the sides are 5.0 cm and 15 cm long, q1 = -5.0 uC, and q2 = +2.0 uC. With V = 0 at infinity, %3D %3D B 42 c. How much work is required to move a charge q3 = +3.0 C from B to A along the diagonals of the rectangle? d. Does this work increase or decrease the electric potential energy of the three- charge system? e. What is the work required if q3 is moved along a path that is inside the rectangle but not on a greater, lesser, or equal diagonal? f. What is the work required if q3 is moved along the path outside the rectangle is 2/6 greater, less, or equal?
Two plates of area 865 x 104 m2 each are separated by a distance of 21.7 x 10-2 m. Calculate the capacitance C of the capacitor. C = F
A conducting sphere of radius 5.0 cm is given a net amount of charge of 3.0 x109 C. Note: 109 C = 1 nC (1 nanocoulomb). What is the potential at a distance of 0.55 m from the center of the sphere? Assume that the electric potential at a very large distance from the sphere equals zero. V = V
The plates of a parallel-plate capacitor have a separation of 4.28 mm, and each has an area of 16.2 cm². Each plate carries a charge of magnitude 5.35x10-8 C. The plates are in vacuum. For related problemsolving tips and strategies, you may want to view a Video Tutor Solution of Properties of a parallel-plate capacitor. What is the capacitance? Express your answer with the appropriate units. C = 3.35x10-12 F Submit Correct Set Up: C = Part B Previous Answers Solve: C = €0 €0 A d V= 2.3107 Part C E = What is the potential difference between the plates? Express your answer with the appropriate units. C = = €0 10 uA Value and V = Ed. 1.62×10-³ m² 4.28x10-³ m Submit Previous Answers Request Answer - 3.35 x 10-12 F V X Incorrect; Try Again; 5 attempts remaining What is the magnitude of the electric field between the plates? Express your answer with the appropriate units. ? Units ?
Figure 1 shows two sets of equi-potential surfaces due to charge q₁ and charge 92. An external agent moves an electron (e = 1.6 × 10-¹⁹ C) from position a to position b. 50 V91 25 V 110 V 110 V 92 50 V Figure 1: Two sets of equi-potential surfaces a) State whether the charges q₁ and q2 are positive or negative. Justify your answer.

SEE MORE QUESTIONS