### Electric Field and Potential Difference Between Conducting Plates**Problem Context:**Two large parallel conducting plates carry opposite charges of equal magnitude and are separated by a distance of 2.20 cm.#### Part A**Question:**If the surface charge density for each plate has a magnitude of \( 47.0 \, \text{nC/m}^2 \), what is the magnitude of \(\mathbf{E}\) in the region between the plates?**Expression of Answer:**- Use the formula to calculate the electric field \( E \) in newtons per coulomb (N/C).- The formula involves inputting \( E \) with the correct units.**Graph/Diagram:**There is no specific graph or diagram associated with this part, only a field for entering the numerical value of \( E \).**Attempted Answer:**The user entered:\[ E = 9 \, \text{N/C} \]which was marked as **Incorrect; Try Again**.#### Part B**Question:**What is the potential difference between the two plates?**Expression of Answer:**- Use the formula to calculate the potential difference \( V \) in volts (V).- The answer is to be expressed in volts with correct units.**Graph/Diagram:**No specific graph or diagram for this part, only a box to input the value of \( V \).#### Part C**Question:**If the separation between the plates is doubled while the surface charge density is kept constant at the value in part (A), what happens to the magnitude of the electric field?**Options:**- Doubles- Stays the same- Halves**Graph/Diagram:**A multiple-choice selection for the response.### Summary of ResponsesFor each part, the user is required to apply principles of electrostatics to determine the correct answers. The questions cover understanding surface charge density’s relationship to the electric field and potential difference, and the impact of changing the separation distance on the electric field.

The seperation between plates is 2.2 cm = 0.022 m.The charge density on the plate is 47 nC/m2.

Two large parallel conducting plates carrying opposite charges of equal magnitude are separated by 2.20 cm. If the surface charge density for each plate has magnitude 47.0 nC/m², what is the magnitude of E in the region between the plates? Express your answer in newtons per coulomb. E = 9 Submit Part B X Incorrect; Try Again V = ΠΙΑΣΦ/ ха Хь = √x vx x Submit Part C Previous Answers Request Answer What is the potential difference between the two plates? Express your answer in volts. Η ΑΣΦ 1 → C Request Answer O doubles O stays the same O halves XIX X.10n S ? ? V p N/C If the separation between the plates is doubled while the surface charge density is kept constant at the value in part (a), what happens to the magnitud the electric field?

Two large parallel conducting plates carrying opposite charges of equal magnitude are separated by 2.20 cm. If the surface charge density for each plate has magnitude 47.0 nC/m², what is the magnitude of E in the region between the plates? Express your answer in newtons per coulomb. E = 9 Submit Part B X Incorrect; Try Again V = ΠΙΑΣΦ/ ха Хь = √x vx x Submit Part C Previous Answers Request Answer What is the potential difference between the two plates? Express your answer in volts. Η ΑΣΦ 1 → C Request Answer O doubles O stays the same O halves XIX X.10n S ? ? V p N/C If the separation between the plates is doubled while the surface charge density is kept constant at the value in part (a), what happens to the magnitud the electric field?

College Physics

11th Edition

ISBN:9781305952300

Author:Raymond A. Serway, Chris Vuille

Publisher:Raymond A. Serway, Chris Vuille

Chapter1: Units, Trigonometry. And Vectors

Section: Chapter Questions

Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...

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