An object with a charge of 17.4 C and a mass of 0.39 kg is travelling horizontally with a speed of 10.5 m/s into the charged plates shown below. The plates are 4.45 m apart, and there is a potential difference of 91 V between the plates. If the charge enters exactly in the middle between the two plates, how far would the charge make it horizontally, in metres, before it bends and collides with the bottom plate? Ignore the force of gravity.
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- The electric field strength between two parallel conducting plates separated by 3.60 cm is 4.90 ✕ 104 V/m. a) What is the potential difference between the plates (in kV)? and b)The plate with the lowest potential is taken to be at zero volts. What is the potential (in V) 1.00 cm from that plate (and 2.60 cm from the other)?(a) Calculate the speed of a proton that is accelerated from rest through an electric potential difference of 144 V. 166.11*10^3 (b) Calculate the speed of an electron that is accelerated through the same potential difference. 7.12*10^6A proton (m=1.67 x 10^-27 kg) travels a distance of 4.3 cm parallel to a uniform electric field 3.5 x 10^5 V/m between the plates shown in the figure. If the initial velocity is 3.2 x 10^5 m/s, find the magnitude of its final velocity in m/s. (Ignore gravity)
- An electron is to be accelerated in a uniform electric field having a strength of 2.106 (a) What energy in keV is given to the electron if it is accelerated through 0.45 m? AKE = keV m (b) Over what distance (in km) would it have to be accelerated to increase its energy by 45 GeV? d = ✔km Hint: How is potential energy, PE, gained by an electron related to the uniform electric field? How is the potential difference, V, related to the uniform electric field?NASA's Deep Space 1 and Dawn spacecraft employed ion thrusters in which xenon ions with a charge of +1.60×10^−19C and a mass of 2.18×10^−25kg are accelerated through a potential difference of 1385 V. What is the speed of the xenon ions as they exit the thruster? Express your answer to three significant figures and include appropriate units.The electric field strength between two parallel conducting plates separated by 4.20 cm is 6.40 ✕ 104 V/m. a) What is the potential difference between the plates (in kV)? and b)The plate with the lowest potential is taken to be at zero volts. What is the potential (in V) 1.40 cm from that plate (and 2.80 cm from the other)?
- A negatively charged particle of mass 4.30 x 10-19 kg is moving with a speed of 35.0 m/s when it enters the region between two parallel capacitor plates. The initial velocity of the charge is parallel to the plate surfaces and in the positive x-direction. The plates are square with a side of 1.00 cm, and the voltage across the plates is 2.50 V. If the particle is initially 1.00 mm from both plates and it just barely clears the positive plate after traveling 1.00 cm through the region between the plates, how many excess electrons are on the particle? Ignore gravitational and edge effects. 35.0 m/s 2.00 mm 1.00 cm Numeric ResponseA small object is connected to a lightweight cord of length L=1.20 m that is tied to a point P, as shown in the figure. The object, string, and point all lie on a frictionless, horizontal table. The object has mass m=.0100kg and charge q= 2.10 uC and is released from rest when the string makes an angle theta=60 with a uniform electric field of magnitude E=260 V/m. Determine the speed in m/a of the object when the string is parallel to the electric field.Two parallel, oppositely-charged, large metal plates are 2.3 cm apart. There is a 19,000 V difference between the plates. A drop of oil with a net charge of 9.1 nC is between the two plates. What is the magnitude of the electric force on the drop?
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