Cathode ray tubes (CRTs) used in old-style televisions have been replaced by modern LCD and LED screens. Part of the CRT included a set of accelerating plates separated by a distance of about 1.20 cm. If the potential difference across the plates was 26.5 kV, find the magnitude of the electric field (in V/m) in the region between the plates.
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Cathode ray tubes (CRTs) used in old-style televisions have been replaced by modern LCD and LED screens. Part of the CRT included a set of accelerating plates separated by a distance of about 1.20 cm. If the potential difference across the plates was 26.5 kV, find the magnitude of the electric field (in V/m) in the region between the plates.
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- An electron is fired at a speed vo = 5.6 x 10° m/s and at an angle 6, = -45° between two parallel conducting plates that are D = 2.0 mm apart, as in Figure P16.72. If the volt- age difference between the plates is AV = 100. V, determine (a) how close, d, the electron will get to the bottom plate and (b) where the electron will strike the top plate. + + + + + + + + Path of the electron AV Figure P16.72An electron is to be accelerated in a uniform electric field having a strength of 0.5 x 106 V/m. What energy in keV is given to the electron if it is accelerated through 0.400 m? 400 keV 800 keV O 100 keV O 200 keVHow far apart (in m) are two conducting plates that have an electric field strength of 4.60 x 103 V/m between them, if their potential difference is 10.5KV
- Review Multiple-Concept Example 4 to see the concepts that are pertinent here. In a television picture tube, electrons strike the screen after being accelerated from rest through a potential difference of 16000 V. The speeds of the electrons are quite large, and for accurate calculations of the speeds, the effects of special relativity must be taken into account. Ignoring such effects, find the electron speed just before the electron strikes the screen. VB =Oppositely charged parallel plates are separated by 6.28 mm. A potential difference of 600 V exists between the plates. (a) What is the magnitude of the electric field between the plates in N/C? (b) What is the magnitude of the force on an electron between the plates in newtons? (c) How much work must be done on the electron to move it to the negative plate if it is initially positioned 2.88 mm from the positive plate in Joules?What is the potential difference between xi = 10 cm and xf = 40 cm in the uniform electric field Ex = 2000 V/m?
- Review Multiple-Concept Example 4 to see the concepts that are pertinent here. In a television picture tube, electrons strike the screen after being accelerated from rest through a potential difference of 24000 V. The speeds of the electrons are quite large, and for accurate calculations of the speeds, the effects of special relativity must be taken into account. Ignoring such effects, find the electron speed just before the electron strikes the screen. VB i eTextbook and Media GO Tutorial Save for Later Attempts: 0 of 6 used Submit AnswerReview Multiple-Concept Example 4 to see the concepts that are pertinent here. In a television picture tube, electrons strike the screen after being accelerated from rest through a potential difference of 21000 V. The speeds of the electrons are quite large, and for accurate calculations of the speeds, the effects of special relativity must be taken into account. Ignoring such effects, find the electron speed just before the electron strikes the screen. VB =Cathode ray tubes (CRTs) used in old-style televisions have been replaced by modern LCD and LED screens. Part of the CRT included a set of accelerating plates separated by a distance of about 1.56 cm. If the potential difference across the plates was 24.0 kV, find the magnitude of the electric field (in V/m) in the region between the plates. ????V/m
- Cathode ray tubes (CRTs) used in old-style televisions have been replaced by modern LCD and LED screens. Part of the CRT included a set of accelerating plates separated by a distance of about 1.32 cm. If the potential difference across the plates was 24.0 kV, find the magnitude of the electric field (in V/m) in the region between the plates.The electric field strength between two parallel conducting plates separated by 3.60 cm is 4.90 ✕ 104 V/m. a) What is the potential difference between the plates (in kV)? and b)The plate with the lowest potential is taken to be at zero volts. What is the potential (in V) 1.00 cm from that plate (and 2.60 cm from the other)?Cathode ray tubes (CRTs) used in old-style televisions have been replaced by modern LCD and LED screens. Part of the CRT included a set of accelerating plates separated by a distance of about 1.30 cm. If the potential difference across the plates was 25.5 kV, find the magnitude of the electric field (in V/m) in the region between the plates. V/m