An electron at point A as shown in the figure has a speed v, = 2.7 × 10° m/s. The distance between points A and B is given as l = 9 cm. (Mass and charge of the electron are m, = 9.109 × 10-31 kg and q. = 1.602 × 10-19 respectively.) A A) Find the magnitude of the magnetic field, in units of microtesla, that will cause the electron to follow the semicircular path from . to B. Answer: B) Find the time, in units of nanoseconds, required for the electron to move from A to B.
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- Asap plzzzzzzA 2.50-kg metallic ball at rest is being pulled by a strange magnetic field of a comet. The force exerted by the comet (in newtons) is given by the function F (r) = –kre-r, where: r: Distance from the comet's surface to the metallic ball, in meters. k =8.00 N m2 a = 2.00 m 1 The metallic ball starts at a distant enough position from the comet such that the force is zero, then starts moving towards the comet. 1. What is the potential function U (r) of the comet? Use the condition U (ro) = lim, 00 U (r) = 0. 2. What is the metallic ball's speed (in m/s) once the steel ball is one meter above the comet? Justify your answer using your rationale and equations used.What is the direction of the magnetic force on current 2 (by the magnetic field of current 1)? What is the magnitude of the magnetic force between currents 1 and 2, in Newtons? I1 = 100 A, I2 = 250 A, both wires are 1.50 m long and the distance between them is 3.00 mm. Your answer needs to have 2 significant figures, including the negative sign in your answer if needed. Do not include the positive sign if the answer is positive. No unit is needed in your answer, it is already given in the question statement.
- - An electron moves along the z-axis with vz 4.7 x 107 m/s. As it passes the origin, what are the strength and direction of the magnetic field at the following (x, y, z) positions? ▾ Part B (0 cm, 0 cm, 1 cm) Express your answers using two significant figures. Enter your answers numerically separated by commas. Bz Bz, By, B₂ = Submit Part C BI, By, B₂ = 15. ΑΣΦ Submit Request Answer (0 cm, 2 cm, 1 cm) Express your answers using two significant figures. Enter your answers numerically separated by commas. VG ΑΣΦ Request Answer ? ? T TFigure 1 shows a long straight wire carrying 1.6 A. An electron 1 cm from a wire moves at 90 m/s in the x-direction. Determine the electron's magnetic force. How many protons may be placed 1 cm from an electron to make its net force zero? FIG. 1.a.) The direction of motion of a proton and the B-field are shown by the arrows in the figure. Find both the magnitude and the direction of the magnetic force. b.) Repeat with an electron instead of a proton. Given: Speed of proton/electron: 1.4 x 10^4 m/s and uniform B-field of 2 T.
- Consider the current-carrying wire shown in the figure. The current creates a magnetic field at the point P, which is the center of the arc segment of the wire. If e = 25.0°, the radius of the arc is 0.700 m, and the current is 2.00 A, what are the magnitude (in nT) and direction of the field produced at P? G magnitude 1.047 Apply the Biot-Savart law. What will be the contributions of the segments of wire along the straight-line sections? Hint: what is ds x f for each segment? nT direction toward the top of the screen X Use the right-hand rule to determine the direction.A magnetic field has a magnitude of 0.00090 T, and an electric field has a magnitude of 4.1 x 103 N/C. Both fields point in the same direction. A positive 2.1-µC charge moves at a speed of 2.5 x 106 m/s in a direction that is perpendicular to both fields. Determine the magnitude of the net force that acts on the charge. Number MI Units B HI 90°At one instant, a proton is at the origin with a velocity (9 × 106, 8 × 106, 4 × 106) m/s. At the observation location (6 × 10-8,3 × 10-8,6 × 10-8) m. A. What is the electric field due to the proton? ( B. What is the magnetic field due to the proton?
- A magnetic field has a magnitude of 0.0010 T, and an electric field has a magnitude of 5.8 x 103 N/C. Both fields point in the same direction. A positive 1.7-µC charge moves at a speed of 4.4 x 106 m/s in a direction that is perpendicular to both fields. Determine the magnitude of the net force that acts on the charge. BA E 90°Consider the figure shown with current 1 = 3.0 A and current 2 = 1 A. What is the magnetic field strength at wire segment b due to current 1 if the distance between the wires is L=3.0 cm Draw the magnetic field from wire 1 and show the direction of this field at segment b. b. What is the resulting force magnitude and direction on wire segment b ( b= 6.0 cm) due to the interaction of current 2 and the magnetic field of current 1? Justify your answer.An electron that is moving through a uniform magnetic field has a velocity v = (46 km/s)i + 40 km/s)j when it experiences a force F = (-4.200×10-15 N)i + (4.830×10-15 N)j due to the magnetic field. If Bx = 0, calculate the magnitude of the magnetic field B. What is Bz?