What is the specific? weight of nitrogen in units of new temper cubeter. at the temperature of minus 10 Celsius and the pressure of 0.6 bar gauge ? Please. I want you to give me details in how you confirm each unit.I don't want answer like I provide. I want another answer with more details. And please, could you use this formula? Specific Weight (γ)=ρ×g =(P(abslot/Rsp*T)×g using idealPV = MRTлие know, тP = PRTr=gas relation-=> mVSpecific weight, r=sgV== density = PPRT(RT) g { 9 = 9-31 1/²g=9.81m/s²101925 x 9.81296.80×263V = 12·81 N/m36specific weight GivenTemperature, T = -10°Cоб, Т= 263 кGuage Pressure, Pg=0.6 bar.Atmospheric Pressure, Patm = 10/325 PaAbsolute Pressure, Pa = Pg + PatmРу = 0-6 bax= 600 раPa == 600 + 101325Pa = 101925 Pasculy(R) Mirogen = 296.80 J/kg-k

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Description: What is the specific? weight of nitrogen in units of new temper cubeter. at the temperature of minus 10 Celsius and the pressure of 0.6 bar gauge ? Please. I want you to give me details in how you confirm each unit.I don't want answer like I provide.

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Elements Of Electromagnetics

7th Edition

ISBN:9780190698614

Author:Sadiku, Matthew N. O.

Publisher:Sadiku, Matthew N. O.

ChapterMA: Math Assessment

Section: Chapter Questions

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What is the specific? weight of nitrogen in units of new temper cubeter. at the temperature of minus 10 Celsius and the pressure of 0.6 bar gauge ?

Please. I want you to give me details in how you confirm each unit.

I don't want answer like I provide. I want another answer with more details. And please, could you use this formula?

Specific Weight (γ)=ρ×g =(P(abslot/Rsp*T)×g

using ideal
PV = MRT
лие know, т
P = P
RT
r=
gas relation-
=> m
V
Specific weight, r=sg
V=
= density = P
P
RT
(RT) g { 9 = 9-31 1/²
g=9.81m/s²
101925 x 9.81
296.80×263
V = 12·81 N/m3
6
specific weight

Given
Temperature, T = -10°C
об, Т= 263 к
Guage Pressure, Pg=0.6 bar.
Atmospheric Pressure, Patm = 10/325 Pa
Absolute Pressure, Pa = Pg + Patm
Ру = 0-6 bax= 600 ра
Pa =
= 600 + 101325
Pa = 101925 Pasculy
(R) Mirogen = 296.80 J/kg-k

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