Question 2.8: Compressed air is commonly used to power a large variety of power tools. Lowe's sells an air compressor that can fill an 8-gallon tank to 160 psi. At a temperature of 70°F, determine the mass of the air inside a full 8-gallon tank. Let Patm = 14.7 psi. a) Use the ideal gas law (you will need to do a lot of unit conversions for this). [0.429 kg] b) Find the compressibility factor. How far off is your analysis above? [0.99]
Question 2.8: Compressed air is commonly used to power a large variety of power tools. Lowe's sells an air compressor that can fill an 8-gallon tank to 160 psi. At a temperature of 70°F, determine the mass of the air inside a full 8-gallon tank. Let Patm = 14.7 psi. a) Use the ideal gas law (you will need to do a lot of unit conversions for this). [0.429 kg] b) Find the compressibility factor. How far off is your analysis above? [0.99]
Elements Of Electromagnetics
7th Edition
ISBN:9780190698614
Author:Sadiku, Matthew N. O.
Publisher:Sadiku, Matthew N. O.
ChapterMA: Math Assessment
Section: Chapter Questions
Problem 1.1MA
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![Question 2.8: Compressed air is commonly used to power a large variety of
power tools.
Lowe's sells an air compressor that can fill an 8-gallon tank to 160 psi. At a temperature
of 70°F, determine the mass of the air inside a full 8-gallon tank. Let Patm = 14.7 psi.
a) Use the ideal gas law (you will need to do a lot of unit conversions for this).
[0.429 kg]
b) Find the compressibility factor. How far off is your analysis above? [0.99]](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F50ae5db4-a69c-4f0f-b55f-4b8988ce32a3%2F86cb6d29-0630-4bdf-9fb7-59d1208b592f%2Fslag45kj_processed.png&w=3840&q=75)
Transcribed Image Text:Question 2.8: Compressed air is commonly used to power a large variety of
power tools.
Lowe's sells an air compressor that can fill an 8-gallon tank to 160 psi. At a temperature
of 70°F, determine the mass of the air inside a full 8-gallon tank. Let Patm = 14.7 psi.
a) Use the ideal gas law (you will need to do a lot of unit conversions for this).
[0.429 kg]
b) Find the compressibility factor. How far off is your analysis above? [0.99]
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