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. Trd² 2 Pori R· Tave Qidea 4 d=1.99225 inches (Peltm + Pfan) (1.04 Parif.9358 inches H₂O R = 287.058 J/Kg.k) Tave 291.7259 Kelvin D=3.101 inches Parm= 362,038 inches H20 Pean-2.0666 inches H20 12

. Trd² 2 Pori R· Tave Qidea 4 d=1.99225 inches (Peltm + Pfan) (1.04 Parif.9358 inches H₂O R = 287.058 J/Kg.k) Tave 291.7259 Kelvin D=3.101 inches Parm= 362,038 inches H20 Pean-2.0666 inches H20 12

Elements Of Electromagnetics
Elements Of Electromagnetics
7th Edition
ISBN:9780190698614
Author:Sadiku, Matthew N. O.
Publisher:Sadiku, Matthew N. O.
ChapterMA: Math Assessment
Section: Chapter Questions
Problem 1.1MA
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please solve for qideal and most importantly provide the units along with it as thats where im strugling and provide the unit conversion to liters/min thank you will upvote if answer is complete neat and explained well just use the equation provided and plug in the variables.   please show the cancelations 

(1.6 04 Qideal 4 2 d 2. Porie · R · Tave (Patm + Pfan) d = 1.99225 inches Parif = .9358 inches H₂O R = 287.058 J/Kg.K) Tave = 291.7259 Kelvin D=3.101 inches Parm= 362,038 inches H₂0 Pean= 2.0666 inches H20 1/2
Transcribed Image Text:(1.6 04 Qideal 4 2 d 2. Porie · R · Tave (Patm + Pfan) d = 1.99225 inches Parif = .9358 inches H₂O R = 287.058 J/Kg.K) Tave = 291.7259 Kelvin D=3.101 inches Parm= 362,038 inches H₂0 Pean= 2.0666 inches H20 1/2
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