I already have the answer and provide it. Show work please (4)3(a)(b)(c)Avap H = 2.93 x 104J/molJa (Avap H = T₂ / H - HIGTcHTsatvapTe sat119.- by HIG= by Tox by TcAvap H = 21,870 J/mol 4. The following data are available for carbon tetrachloride:HGHc (1 cal = 4.184 J)Vapor pressure (MPa) 0.5065Temperature (°C)141.7Using this information, complete the following:(a) Compute the heat of vaporization (AvapH) of carbon tetrachloride at 200 °C (inJ mol-¹).15.0(b) Derive the following expression, which can be used to compute the heat ofvaporization from the principle of corresponding states:14.013.012.011.0I10.0 ++I9.07.0(c) Compute the heat of vaporization of carbon tetrachloride at 200 °C (in J mol-¹)using the principle of corresponding states. (Hint: Figure 6.6-4 will be useful forsolving this part of the problem)8.0 H6.05.04.03.02.01.00I0.75I1IT1I*Starting with the following equation: AvapH = (HV) sat -vap1I0.1Saturated liquid,Iil0.80!IilIl|T||1TI0.8511ITc283.3 °C and P = 4.56 MPa and Zc = 0.27211IJIIIIISaturated gas090-7|||||| I11HI0.90AvapH = Tc0.95LIN¡0.921 iII10.941 1i!0.961I T 110.98||||| !II TII||0.2 0.3 0.4 0.5il~ - (²-1)H - HIGsatTcvap2.001.0H-HIGTcT,3.002.0Reduced pressure, P,Generalized enthalpy departurefrom ideal gas behavior(per mole of gas or liquid, Z = 0.27)+0.50*0.60*0.70-0.800.900.94-0.981.021.06'1.10.1.201.301.013178.01.501.701.902.202.603.003.0 4.0 5.00.550.650.750.850.920.961.01.041.081.151.251.401.601.802.002.402.80+4.001010A200.500.550.600.650.800.901.001.101.301.40satliq0.700.70-9.01.50- (H¹) s2.6015.014.04.003.0013.03012.011.01.20 5.010.08.07.06.04.01.601.802.001.03.02.202.4002.02.80-1.02.026222.0-2.0satvap

The following data are available for carbon tetrachloride: Tc = 283.3 °C and P = 4.56 MPa and Zc = 0.272 Vapor pressure (MPa) 0.5065 Temperature (°C) 141.7 1.013 178.0 2.026 222.0 Using this information, complete the following: (a) Compute the heat of vaporization (AvapH) of carbon tetrachloride at 200 °C (in J mol-¹).

The following data are available for carbon tetrachloride: Tc = 283.3 °C and P = 4.56 MPa and Zc = 0.272 Vapor pressure (MPa) 0.5065 Temperature (°C) 141.7 1.013 178.0 2.026 222.0 Using this information, complete the following: (a) Compute the heat of vaporization (AvapH) of carbon tetrachloride at 200 °C (in J mol-¹).

Elements Of Electromagnetics

7th Edition

ISBN:9780190698614

Author:Sadiku, Matthew N. O.

Publisher:Sadiku, Matthew N. O.

ChapterMA: Math Assessment

Section: Chapter Questions

Problem 1.1MA

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Concept explainers

Properties of Pure Substances

A substance with fixed chemical composition throughout is called a pure substance like water, air, and nitrogen. A pure substance does not have to be a single element or compound. A mixture of two or more phases of a pure substance is also a pure substance as long as the chemical composition is the same for all phases. These substances mainly have a constant/ uniform composition. The substances also have fixed boiling and melting points. A pure substance takes part in a chemical reaction to form predictable products.

Question

I already have the answer and provide it. Show work please

(4)
3
(a)
(b)
(c)
Avap H = 2.93 x 104J/mol
Ja (
Avap H = T₂ / H - HIG
Tc
H
T
sat
vap
Te sat
119.
- by HIG
= by To
x by Tc
Avap H = 21,870 J/mol

4. The following data are available for carbon tetrachloride:
HGHc (1 cal = 4.184 J)
Vapor pressure (MPa) 0.5065
Temperature (°C)
141.7
Using this information, complete the following:
(a) Compute the heat of vaporization (AvapH) of carbon tetrachloride at 200 °C (in
J mol-¹).
15.0
(b) Derive the following expression, which can be used to compute the heat of
vaporization from the principle of corresponding states:
14.0
13.0
12.0
11.0
I
10.0 ++
I
9.0
7.0
(c) Compute the heat of vaporization of carbon tetrachloride at 200 °C (in J mol-¹)
using the principle of corresponding states. (Hint: Figure 6.6-4 will be useful for
solving this part of the problem)
8.0 H
6.0
5.0
4.0
3.0
2.0
1.0
0
I
0.75
I
1
I
T
1
I
*Starting with the following equation: AvapH = (HV) sat -
vap
1
I
0.1
Saturated liquid,
I
il
0.80
!
I
il
Il
|
T
||
1
T
I
0.85
11
I
Tc283.3 °C and P = 4.56 MPa and Zc = 0.272
11
I
J
I
I
I
I
I
Saturated gas
090-7
|||
||| I
11
HI
0.90
AvapH = Tc
0.95
LIN
¡0.921 i
II
10.941 1
i
!0.961
I T 110.98
||
||| !I
I T
II
||
0.2 0.3 0.4 0.5
il
~ - (²-1)
H - HIG
sat
Tc
vap
2.00
1.0
H-HIG
Tc
T,
3.00
2.0
Reduced pressure, P,
Generalized enthalpy departure
from ideal gas behavior
(per mole of gas or liquid, Z = 0.27)
+0.50
*0.60
*0.70
-0.80
0.90
0.94
-0.98
1.02
1.06'
1.10.
1.20
1.30
1.013
178.0
1.50
1.70
1.90
2.20
2.60
3.00
3.0 4.0 5.0
0.55
0.65
0.75
0.85
0.92
0.96
1.0
1.04
1.08
1.15
1.25
1.40
1.60
1.80
2.00
2.40
2.80+
4.00
10
10
A
20
0.50
0.55
0.60
0.65
0.80
0.90
1.00
1.10
1.30
1.40
sat
liq
0.70
0.70-9.0
1.50
- (H¹) s
2.60
15.0
14.0
4.00
3.00
13.0
30
12.0
11.0
1.20 5.0
10.0
8.0
7.0
6.0
4.0
1.60
1.80
2.001.0
3.0
2.20
2.400
2.0
2.80-1.0
2.026
222.0
-2.0
sat
vap

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