**Question:**What is the minimum change of entropy that occurs in 0.200 kg of ice at 273 K when \(7.40 \times 10^4\) J of heat is added so that it melts to water?**Options:**- \(2.71 \times 10^2\) J/K- \(3.69 \times 10^{-3}\) J/K- \(7.4 \times 10^4\) J/K- \(3.11 \times 10^2\) J/K- \(3.22 \times 10^{-3}\) J/K

Given data: The given temperature, T=273 K The energy heat is dQ=7.40×104 JExplanation: The expression change in entropy due to a change in heat, △S=dQT Substituting the given value in the above expression, △S=7.40×104273=271.06=2.71×102 J/K Hence, option (a) is correct. Hence, the minimum change of entropy is 2.71×102 J/K.

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What is the minimum change of entropy that occurs in 0.200 kg of ice at 273 K when 7.40 x 104 J of heat is added so that it melts to water? O 2.71 x 10² J/K O 3.69 x 10-3 J/K O 7.4 x 104 J/K O 3.11 x 10² J/K O 3.22 x 10³ J/K

What is the minimum change of entropy that occurs in 0.200 kg of ice at 273 K when 7.40 x 104 J of heat is added so that it melts to water? O 2.71 x 10² J/K O 3.69 x 10-3 J/K O 7.4 x 104 J/K O 3.11 x 10² J/K O 3.22 x 10³ J/K

College Physics

11th Edition

ISBN:9781305952300

Author:Raymond A. Serway, Chris Vuille

Publisher:Raymond A. Serway, Chris Vuille

Chapter1: Units, Trigonometry. And Vectors

Section: Chapter Questions

Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...

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