What is the theoretical maximum efficiency of a heat engine (Carnot engine) operating between 150.0 C and 400.0 C? O 0.3714 O 0.6250 O 0.3750 O 0.2500 O 0.3560
What is the theoretical maximum efficiency of a heat engine (Carnot engine) operating between 150.0 C and 400.0 C? O 0.3714 O 0.6250 O 0.3750 O 0.2500 O 0.3560
College Physics
11th Edition
ISBN:9781305952300
Author:Raymond A. Serway, Chris Vuille
Publisher:Raymond A. Serway, Chris Vuille
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![**Question:**
What is the theoretical maximum efficiency \( e \) of a heat engine (Carnot engine) operating between 150.0°C and 400.0°C?
**Options:**
- ○ 0.3714
- ○ 0.6250
- ○ 0.3750
- ○ 0.2500
- ○ 0.3560
**Explanation:**
The theoretical maximum efficiency of a Carnot engine can be calculated using the formula:
\[ e = 1 - \frac{T_c}{T_h} \]
where:
- \( T_c \) is the absolute temperature of the cold reservoir (in Kelvin)
- \( T_h \) is the absolute temperature of the hot reservoir (in Kelvin)
To convert from Celsius to Kelvin, add 273.15 to the Celsius temperature.
For this problem:
- \( T_h = 400.0°C + 273.15 = 673.15 \, \text{K} \)
- \( T_c = 150.0°C + 273.15 = 423.15 \, \text{K} \)
Plug these values into the efficiency formula to find the theoretical maximum efficiency.](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F22da6f86-1937-4ce6-83a9-97c297078de9%2Fcdabdf31-48bd-4eb7-bd66-111462da6e3d%2F6ruajym_processed.png&w=3840&q=75)
Transcribed Image Text:**Question:**
What is the theoretical maximum efficiency \( e \) of a heat engine (Carnot engine) operating between 150.0°C and 400.0°C?
**Options:**
- ○ 0.3714
- ○ 0.6250
- ○ 0.3750
- ○ 0.2500
- ○ 0.3560
**Explanation:**
The theoretical maximum efficiency of a Carnot engine can be calculated using the formula:
\[ e = 1 - \frac{T_c}{T_h} \]
where:
- \( T_c \) is the absolute temperature of the cold reservoir (in Kelvin)
- \( T_h \) is the absolute temperature of the hot reservoir (in Kelvin)
To convert from Celsius to Kelvin, add 273.15 to the Celsius temperature.
For this problem:
- \( T_h = 400.0°C + 273.15 = 673.15 \, \text{K} \)
- \( T_c = 150.0°C + 273.15 = 423.15 \, \text{K} \)
Plug these values into the efficiency formula to find the theoretical maximum efficiency.
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