What happens to the values of the registers at each step when the program in memory is run on the following system. Assume that memory words are 16bits and 4-bit is reserved for opcode, 12-bit is reserved for addresses. Assume that the value of 8 comes from the device number 5. (the memory address and its contents are given in hexadecimal) CPU 0001 (1h) = LOAD AC from memory 0011 (3h) = Compare the value of the given device to the value of the AC. The result is stored in eq. flag 0111(7h) = If the equality flag is 1, continue with the given address (JMPEQ) 111(Fh) = Load the given address value into the PC, ie jump to given address |(JMP) МЕМORY PC MAR ADDRESS VALUE 300 1940 301 3005 7304 302 303 IR MBR F301 AC Execution Unit 1/O AR 940 0003

Database System Concepts
7th Edition
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1. What happens to the values of the registers at each step when the program in memory is
run on the following system. Assume that memory words are 16bits and 4-bit is reserved
for opcode, 12-bit is reserved for addresses. Assume that the value of 8 comes from the
device number 5. (the memory address and its contents are given in hexadecimal)
CPU
o001 (1h) = LOAD AC from memory
0011 (3h) = Compare the value of the given device to the value of the AC. The
result is stored in eq. flag
|0111(7h) = If the equality flag is 1, continue with the given address (JMPEQ)
1111(Fh) = Load the given address value into the PC, ie jump to given address
(JMP)
МЕМORY
PC
MAR
ADDRESS VALUE
300
301
302
303
1940
3005
IR
MBR
7304
F301
AC
Execution
Unit
1/O AR
940
0003
1/O BR
VO Module
Buffers
Transcribed Image Text:1. What happens to the values of the registers at each step when the program in memory is run on the following system. Assume that memory words are 16bits and 4-bit is reserved for opcode, 12-bit is reserved for addresses. Assume that the value of 8 comes from the device number 5. (the memory address and its contents are given in hexadecimal) CPU o001 (1h) = LOAD AC from memory 0011 (3h) = Compare the value of the given device to the value of the AC. The result is stored in eq. flag |0111(7h) = If the equality flag is 1, continue with the given address (JMPEQ) 1111(Fh) = Load the given address value into the PC, ie jump to given address (JMP) МЕМORY PC MAR ADDRESS VALUE 300 301 302 303 1940 3005 IR MBR 7304 F301 AC Execution Unit 1/O AR 940 0003 1/O BR VO Module Buffers
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