00 01 02 00 01 02 Memory contents 5800 1801 6800 001E 000A loooc A Program

Database System Concepts
7th Edition
ISBN:9780078022159
Author:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan
Publisher:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan
Chapter1: Introduction
Section: Chapter Questions
Problem 1PE
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Question
1. (5) Run the following program where PC starts from memory address 100
address
100
101
102
800
801
802
memory address 800 contents:
2. (5) Run the following program where PC starts from 210
address
210
211
212
800
Question: 1) Upon the completion of the program, what will be the contents of the following memory address?
801
802
Memory
memory address 801 contents:
contents
• Answer all questions with hexadecimal.
5800
1801
6800
001E
000A
loooc
Memory
contents
5801
2802
6801
FFFE
000A
Question: 2) Upon the completion of the program, what will be the contents of the following memory address?
0005
A Program
A Program
Transcribed Image Text:1. (5) Run the following program where PC starts from memory address 100 address 100 101 102 800 801 802 memory address 800 contents: 2. (5) Run the following program where PC starts from 210 address 210 211 212 800 Question: 1) Upon the completion of the program, what will be the contents of the following memory address? 801 802 Memory memory address 801 contents: contents • Answer all questions with hexadecimal. 5800 1801 6800 001E 000A loooc Memory contents 5801 2802 6801 FFFE 000A Question: 2) Upon the completion of the program, what will be the contents of the following memory address? 0005 A Program A Program
Consider the following instruction format and the list of opcodes
0101
*Note that all memory contents and addresses are hexadecimal.
0110
0001
0010
0011
Opcode (15.12)
0100
Instruction format
Opcode
Address(11..0)
A portion of the instruction set
Load AC from memory
Store AC to memory
Instruction
Add AC from memory - AC + memory
Subtract memory from AC - AC - memory
Multiply AC by memory - AC*memory
Divide AC by memory- AC/memory
Transcribed Image Text:Consider the following instruction format and the list of opcodes 0101 *Note that all memory contents and addresses are hexadecimal. 0110 0001 0010 0011 Opcode (15.12) 0100 Instruction format Opcode Address(11..0) A portion of the instruction set Load AC from memory Store AC to memory Instruction Add AC from memory - AC + memory Subtract memory from AC - AC - memory Multiply AC by memory - AC*memory Divide AC by memory- AC/memory
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