Suppose you have a computer with a main memory that isword-addressable and has a size of 32K x 16. Theassembly program's instruction set consists of 400 differentoperations. All instructions have an operation code part(opcode) and an address part, allowing for only oneaddress. Each instruction is stored in one word of memory.a. Determine the number of bits needed for the opcode.b. Calculate the number of bits available for the addresspart of the instruction.c. Find out how many additional instructions could be addedto this instruction set without exceeding the assignednumber of bits. Discuss and show your calculations.d. Determine the largest unsigned binary number that theaddress can hold.

Determining the amount of bits required for different components of an instruction is a step in the…

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Consider the following instruction format and the list of opcodes 0101 *Note that all memory contents and addresses are hexadecimal. 0110 0001 0010 0011 Opcode (15.12) 0100 Instruction format Opcode Address(11..0) A portion of the instruction set Load AC from memory Store AC to memory Instruction Add AC from memory - AC + memory Subtract memory from AC - AC - memory Multiply AC by memory - AC*memory Divide AC by memory- AC/memory
Suppose you have a computer with a main memory that is word-addressable and has a size of 32K x 16. The assembly program's instruction set consists of 400 different operations. All instructions have an operation code part (opcode) and an address part, allowing for only one address. Each instruction is stored in one word of memory. a. Determine the number of bits needed for the opcode. b. Calculate the number of bits available for the address part of the instruction. c. Find out how many additional instructions could be added to this instruction set without exceeding the assigned number of bits. Discuss and show your calculations. d. Determine the largest unsigned binary number that the address can hold.
Please answer all the following questions. 1. In a hypothetical computer, the processor has four registers: an 8-bit Program Counter (PC), a 16-bit Accumulator (AC), a 16-bit Counter (CTR), and a 12-bit Pointer (PTR). The memory is divided into words each of which is 16-bit long. Each word can hold either an instruction or a piece of data. For each instruction X, the four most significant bits (denoted by X15-12) represent an opcode. The rest of the instruction (denoted by X11-0) can be either an address or a value of an operand. The table below explains some of the instructions supported by the processor. Opcode (binary) 0000 0001 0010 0011 0100 0101 0110 0111 1000 1001 1010 1011 Operation Load AC from a memory location whose address is X11-0. Store AC into a memory location whose address is X11-0. Add to AC the contents of a memory location whose address is the value of PTR. The result is saved to AC. 1100 Subtract from AC the contents of a memory location whose address is the value…
Computer Architecture (Already submit this question, but I think I got wrong solution) Consider a computer that has a number of registers such that the three registers R0 =1500, R1 = 4500, and R2 = 1000 Show the effective address of memory and the registers’ contents in each of the following instructions 1. ADD (R1), R2 2. MOVE 500(R0), R2 3. ADD (40), R1 4. SUBTRACT (5000), R2 5. ADD #30, R2
Suppose a computer has 32-bit instructions. The instruction set consists of 64 different operations. All instructions have an opcode and two address fields (allowing for two addresses). The first of these addresses must be a register direct address, and the second must be a memory address. Expanding opcodes are not used. The machine has 16 registers. How many bits can be used for the memory address?
A digital computer has a memory unit with 32 bits per word. The instruction set consists of 110 different operations. All instructions have an operation code part (opcode) and two address fields: one for a memory address and one for a register address. This particular system includes eight general-purpose, user-addressable registers. Registers may be loaded directly from memory, and memory may be updated directly from the registers. Direct memory-to-memory data movement operations are not supported. Each instruction stored in one word of memory. At least, how many bits are needed for the opcode?