What does the confidence interval suggest about the effectiveness of the​ treatment?   A. The confidence interval limits contain ​0, suggesting that the garlic treatment  affect the LDL cholesterol levels.   B. The confidence interval limits do not contain 0, suggesting that the garlic treatment  affect the LDL cholesterol levels.   C. The confidence interval limits do not contain ​0, suggesting that the garlic treatment  affect the LDL cholesterol levels.

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What does the confidence interval suggest about the effectiveness of the​ treatment?

 


A. The confidence interval limits contain ​0, suggesting that the garlic treatment  affect the LDL cholesterol levels.

 

B. The confidence interval limits do not contain 0, suggesting that the garlic treatment  affect the LDL cholesterol levels.

 

C. The confidence interval limits do not contain ​0, suggesting that the garlic treatment  affect the LDL cholesterol levels.

 

D. The confidence interval limits contain 0, suggesting that the garlic treatment  affect the LDL cholesterol levels.

**Positive z Scores**

This table provides a comprehensive guide to positive z-scores and their corresponding cumulative area from the left under the standard normal distribution curve.

**Graph Explanation:**
At the top of the image, a bell curve is illustrated, showing the normal distribution. The curve is shaded to the left of the given z-score, indicating the cumulative area from the left. 

**Table Explanation:**
The table is organized with z-scores rounded to two decimal places. The rows indicate the z-score's whole number and first decimal place, while the columns represent the second decimal place. 

Each cell in the table shows the cumulative probability from the left up to that z-score. For example, to find the cumulative probability for a z-score of 1.23, locate the row for 1.2 and move to the column under .03. The value is 0.8907, which is the cumulative probability.

**Common Critical Values:**
Some commonly used critical values are noted at the bottom right of the table:

- 90% (z = 1.645)
- 95% (z = 1.960)
- 99% (z = 2.576)

**Note:**
For z-values of 3.50 and larger, use 0.9999 for the area.

This table is an essential tool for statistical analysis, particularly for determining probabilities and critical values associated with positive z-scores in a standard normal distribution.
Transcribed Image Text:**Positive z Scores** This table provides a comprehensive guide to positive z-scores and their corresponding cumulative area from the left under the standard normal distribution curve. **Graph Explanation:** At the top of the image, a bell curve is illustrated, showing the normal distribution. The curve is shaded to the left of the given z-score, indicating the cumulative area from the left. **Table Explanation:** The table is organized with z-scores rounded to two decimal places. The rows indicate the z-score's whole number and first decimal place, while the columns represent the second decimal place. Each cell in the table shows the cumulative probability from the left up to that z-score. For example, to find the cumulative probability for a z-score of 1.23, locate the row for 1.2 and move to the column under .03. The value is 0.8907, which is the cumulative probability. **Common Critical Values:** Some commonly used critical values are noted at the bottom right of the table: - 90% (z = 1.645) - 95% (z = 1.960) - 99% (z = 2.576) **Note:** For z-values of 3.50 and larger, use 0.9999 for the area. This table is an essential tool for statistical analysis, particularly for determining probabilities and critical values associated with positive z-scores in a standard normal distribution.
In a study examining the effectiveness of garlic in lowering cholesterol, 48 subjects were treated with garlic in a processed tablet form. Cholesterol levels were measured before and after the treatment. The differences in their LDL cholesterol levels (measured in mg/dL), calculated as the values before treatment minus those after treatment, showed a mean of 4.1 with a standard deviation of 17.2. 

The task is to construct a 95% confidence interval estimate of the mean net change in LDL cholesterol following the garlic treatment. Additionally, the confidence interval may provide insights into the effectiveness of garlic in reducing LDL cholesterol levels.

Resources for additional data analysis include:
- Click here to view a t distribution table.
- Click here to view page 1 of the standard normal distribution table.
- Click here to view page 2 of the standard normal distribution table.

The question is: What is the confidence interval estimate of the population mean μ?

The format provided for the answer is:
\[ \text{mg/dL} < \mu < \text{mg/dL} \]
(Results should be rounded to two decimal places as needed.)
Transcribed Image Text:In a study examining the effectiveness of garlic in lowering cholesterol, 48 subjects were treated with garlic in a processed tablet form. Cholesterol levels were measured before and after the treatment. The differences in their LDL cholesterol levels (measured in mg/dL), calculated as the values before treatment minus those after treatment, showed a mean of 4.1 with a standard deviation of 17.2. The task is to construct a 95% confidence interval estimate of the mean net change in LDL cholesterol following the garlic treatment. Additionally, the confidence interval may provide insights into the effectiveness of garlic in reducing LDL cholesterol levels. Resources for additional data analysis include: - Click here to view a t distribution table. - Click here to view page 1 of the standard normal distribution table. - Click here to view page 2 of the standard normal distribution table. The question is: What is the confidence interval estimate of the population mean μ? The format provided for the answer is: \[ \text{mg/dL} < \mu < \text{mg/dL} \] (Results should be rounded to two decimal places as needed.)
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