4. co KLLTLUJIUI III USed a Sample of IndiMiduals to rate the purchase potential of a particular product before and after the individuals saw a new television commercial about the product. The purchase potential ratings were based on a 0 to 10 scale, with higher values indicatinc higher purchase potential. The null hypothesis stated that the mean rating "after" would be less than or equal to the mean rating "before." Rejection of this hypothesis would show that the commercial improved the mean purchase potential rating. Use a= 0.05 and the following da test the hypothesis and comment on the value of the commercial. Purchase Rating Individual After Before 6 2 6 4. 4 3 3 9 8. 7 6. State the null and alternative hypotheses. (Use u = mean rating after - mean rating before.) O H: = 0 O H: H>0 05 Pr:H O O Hi H #0 Hi4 = 0 Calculate the value of the test statistic. (Round your answer to three decimal places.) Calculate the p-value. (Round your answer to four decimal places.) p-value = State your conclusion. O Do not Reject H There is sufficient evidence to conclude that seeing the commercial improves the mean potential to purchase. O Do not reject H There is insufficient evidence to conclude that seeing the commercial improves the mean potential to purchase. O Reject H There is insufficient evidence to conclude that seeing the commercial improves the mean potential to purchase.

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A market research firm used a sample of individuals to rate the purchase potential of a particular product before and after the individuals saw a new television commercial about the product. The purchase potential ratings were based on a 0 to 10 scale, with higher values being better. The firm would like to test the hypothesis and comment on the value of the commercial. Use α = 0.05 and the following data.

**Purchase Rating Table:**

| Individual | After | Before |
|------------|-------|--------|
| 1          | 8     | 5      |
| 2          | 6     | 5      |
| 3          | 4     | 3      |
| 4          | 5     | 4      |
| 5          | 3     | 2      |
| 6          | 1     | 1      |

- State the null and alternative hypotheses. (Use μₐ = mean rating after; μ_b = mean rating before.)

    - \( H_0: \mu_a = \mu_b \)
    - \( H_1: \mu_a \neq \mu_b \)

- Calculate the value of the test statistic. (Round your answer to three decimal places.)

- Calculate the p-value. (Round your answer to four decimal places.)

- State your conclusion:
    - Reject \( H_0 \). There is sufficient evidence to conclude that the commercial improves the mean potential to purchase.
    - Do not reject \( H_0 \). There is insufficient evidence to conclude that the commercial improves the mean potential to purchase.

To be complete the test, you would calculate the differences between the "After" and "Before" ratings, compute the mean and standard deviation of these differences, and then determine the t-test statistic and p-value accordingly.
Transcribed Image Text:A market research firm used a sample of individuals to rate the purchase potential of a particular product before and after the individuals saw a new television commercial about the product. The purchase potential ratings were based on a 0 to 10 scale, with higher values being better. The firm would like to test the hypothesis and comment on the value of the commercial. Use α = 0.05 and the following data. **Purchase Rating Table:** | Individual | After | Before | |------------|-------|--------| | 1 | 8 | 5 | | 2 | 6 | 5 | | 3 | 4 | 3 | | 4 | 5 | 4 | | 5 | 3 | 2 | | 6 | 1 | 1 | - State the null and alternative hypotheses. (Use μₐ = mean rating after; μ_b = mean rating before.) - \( H_0: \mu_a = \mu_b \) - \( H_1: \mu_a \neq \mu_b \) - Calculate the value of the test statistic. (Round your answer to three decimal places.) - Calculate the p-value. (Round your answer to four decimal places.) - State your conclusion: - Reject \( H_0 \). There is sufficient evidence to conclude that the commercial improves the mean potential to purchase. - Do not reject \( H_0 \). There is insufficient evidence to conclude that the commercial improves the mean potential to purchase. To be complete the test, you would calculate the differences between the "After" and "Before" ratings, compute the mean and standard deviation of these differences, and then determine the t-test statistic and p-value accordingly.
Expert Solution
Step 1

Answer:

from the above information

mean=d¯ =0.625

standard deviation =sd(d)¯=1.302

sample size = n =8

the hypothesis is 

H0μd  0

H1 : μd  = 0

The test statistic is 

t=d¯sd(d)/n¯

t=0.6251.302/8

t=1.357

the value of test statistic t=1.357

p vale

by using p value table of t distribution with test statistic t=1.357 and degree of freedom =n-1=8-1=7

p value =0.1385

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