Test the claim that the proportion of people who own cats is significantly different than 80% at the 0.1 significance level. The null and alternative hypothesis would be: H0:μ=0.8H0:μ=0.8 H1:μ≠0.8H1:μ≠0.8 H0:p=0.8H0:p=0.8 H1:p≠0.8H1:p≠0.8 H0:p≤0.8H0:p≤0.8 H1:p>0.8H1:p>0.8 H0:p≥0.8H0:p≥0.8 H1:p<0.8H1:p<0.8 H0:μ≤0.8H0:μ≤0.8 H1:μ>0.8H1:μ>0.8 H0:μ≥0.8H0:μ≥0.8 H1:μ<0.8H1:μ<0.8 The test is: right-tailed left-tailed two-tailed Based on a sample of 200 people, 87% owned cats The p-value is: (to 2 decimals) Based on this we: Reject the null hypothesis Fail to reject the null hypothesis

Test the claim that the proportion of people who own cats is significantly different than 80% at the 0.1 significance level. The null and alternative hypothesis would be: H0:μ=0.8H0:μ=0.8 H1:μ≠0.8H1:μ≠0.8 H0:p=0.8H0:p=0.8 H1:p≠0.8H1:p≠0.8 H0:p≤0.8H0:p≤0.8 H1:p>0.8H1:p>0.8 H0:p≥0.8H0:p≥0.8 H1:p<0.8H1:p<0.8 H0:μ≤0.8H0:μ≤0.8 H1:μ>0.8H1:μ>0.8 H0:μ≥0.8H0:μ≥0.8 H1:μ<0.8H1:μ<0.8 The test is: right-tailed left-tailed two-tailed Based on a sample of 200 people, 87% owned cats The p-value is: (to 2 decimals) Based on this we: Reject the null hypothesis Fail to reject the null hypothesis

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Description: Test the claim that the proportion of people who own cats is significantly different than 80% at the 0.1 significance level.The null and alternative hypothesis would be: H0:μ=0.8H0:μ=0.8H1:μ≠0.8H1:μ≠0.8H0:p=0.8H0:p=0.8H1:p≠0.8H1:p≠0.8H0:p≤0.8H0:p≤0.8

A First Course in Probability (10th Edition)

10th Edition

ISBN:9780134753119

Author:Sheldon Ross

Publisher:Sheldon Ross

Chapter1: Combinatorial Analysis

Section: Chapter Questions

Problem 1.1P: a. How many different 7-place license plates are possible if the first 2 places are for letters and...

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Concept explainers

2-Proportion Test

In a 2-proportion test, two separate proportions are measured at the same time, and their similarity is evaluated. It is also known as a 2-proportion z-test, and a comparison of two different proportions is done in this method.

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Question

Test the claim that the proportion of people who own cats is significantly different than 80% at the 0.1 significance level.

The null and alternative hypothesis would be:

H0:μ=0.8H0:μ=0.8
H1:μ≠0.8H1:μ≠0.8

H0:p=0.8H0:p=0.8
H1:p≠0.8H1:p≠0.8

H0:p≤0.8H0:p≤0.8
H1:p>0.8H1:p>0.8

H0:p≥0.8H0:p≥0.8
H1:p<0.8H1:p<0.8

H0:μ≤0.8H0:μ≤0.8
H1:μ>0.8H1:μ>0.8

H0:μ≥0.8H0:μ≥0.8
H1:μ<0.8H1:μ<0.8

The test is:

right-tailed

left-tailed

two-tailed

Based on a sample of 200 people, 87% owned cats

The p-value is: (to 2 decimals)

Based on this we:

Reject the null hypothesis
Fail to reject the null hypothesis

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Test the claim that the proportion of men who own cats is smaller than the proportion of women who own cats at the .10 significance level.The null and alternative hypothesis would be: H0:pM=pFH0:pM=pFH1:pM>pFH1:pM>pF H0:μM=μFH0:μM=μFH1:μM<μFH1:μM<μF H0:μM=μFH0:μM=μFH1:μM≠μFH1:μM≠μF H0:pM=pFH0:pM=pFH1:pM≠pFH1:pM≠pF H0:μM=μFH0:μM=μFH1:μM>μFH1:μM>μF H0:pM=pFH0:pM=pFH1:pM<pFH1:pM<pF The test is: left-tailed two-tailed right-tailed Based on a sample of 40 men, 35% owned catsBased on a sample of 20 women, 45% owned catsThe test statistic is:  (to 2 decimals)The p-value is:  (to 2 decimals)Based on this we: Fail to reject the null hypothesis Reject the null hypothesis
Test the claim that the proportion of people who own cats is significantly different than 40% at the 0.05 significance level.The null and alternative hypothesis would be: H0:p≥0.4H0:p≥0.4H1:p<0.4H1:p<0.4 H0:μ≤0.4H0:μ≤0.4H1:μ>0.4H1:μ>0.4 H0:μ≥0.4H0:μ≥0.4H1:μ<0.4H1:μ<0.4 H0:p≤0.4H0:p≤0.4H1:p>0.4H1:p>0.4 H0:p=0.4H0:p=0.4H1:p≠0.4H1:p≠0.4 H0:μ=0.4H0:μ=0.4H1:μ≠0.4H1:μ≠0.4 The test is: two-tailed left-tailed right-tailed Based on a sample of 700 people, 44% owned catsThe test statistic is:  (to 2 decimals)The p-value is:  (to 2 decimals)Based on this we: Reject the null hypothesis Fail to reject the null hypothesis
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The Venn diagram below shows the 15 students in Ms. Johnson's class. The diagram shows the memberships for the Chess Club and the Basketball Club. Note that "Mai" is outside the circles since she is not a member of either club. One student from the class is randomly selected. Let A denote the event "the student is in the Chess Club." Let B denote the event "the student is in the Basketball Club." (a) Find the probabilities of the events below. Write each answer as a single fraction. P(A) = P(B) = P(A or B) = P(4_and_ B) = || P(A) + P(B) − P (4 and B) = (b) Select the probability that is equal to P (A) + P (B) − P (A and B). OP (A) OP(A and B) OP (B) OP (A or B) olo ? Mai Chess David Christine Tom Basketball Justin Ashley Maria Mary Dante Amy Lamar Lena Chris Rainal Miguel
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