what decision can you make and what does that mean?  b. calculate and evaluate cohens d  c. what type of error could you be making

MATLAB: An Introduction with Applications
6th Edition
ISBN:9781119256830
Author:Amos Gilat
Publisher:Amos Gilat
Chapter1: Starting With Matlab
Section: Chapter Questions
Problem 1P
icon
Related questions
Question

a. what decision can you make and what does that mean? 

b. calculate and evaluate cohens d 

c. what type of error could you be making 

A psychiatrist wants to test a drug claimed to decrease anxiety episodes in depressed
patients. A group of n = 50 subjects participates in her program and their anxiety
episodes are counted. The sample produces M = 22.78, s 5.63. It is known that
the population value for this measure is m 25. Test the hypothesis that the
program decreases anxiety episodes. Test with a = .01.
%D
%3D
Transcribed Image Text:A psychiatrist wants to test a drug claimed to decrease anxiety episodes in depressed patients. A group of n = 50 subjects participates in her program and their anxiety episodes are counted. The sample produces M = 22.78, s 5.63. It is known that the population value for this measure is m 25. Test the hypothesis that the program decreases anxiety episodes. Test with a = .01. %D %3D
Expert Solution
Step 1

a.

Let μ denotes the population mean. The claim of the test is that anxiety episodes in depressed patients decreased. The hypothesis is,

Null hypothesis:

H0:μ25

Alternative hypothesis:

Ha:μ<25

The test statistic is,

t=M-msn=22.78-255.6350=-2.220.7962=-2.7882

The test statistic is -2.7882.

The degrees of freedom is,

df=n-1=50-1=49

The degrees of freedom is 49.

The hypothesis is left tail. The probability of t less than –2.7882 with 49 degrees of freedom can be obtained using the excel formula “=T.DIST(–2.7882,49,TRUE)”.The p-value is 0.0038.

Decision rule:

If p-value≤α, then reject the null hypothesis. Otherwise, do not reject the null hypothesis.

Conclusion:

The p-value (0.0038) is less than the level of significance (0.01).

Based on decision rule, reject the null hypothesis.

Thus, there is no sufficient evidence that the mean anxiety episodes in depressed patients decreased.

steps

Step by step

Solved in 2 steps

Blurred answer
Knowledge Booster
Statistical Power and Errors
Learn more about
Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, statistics and related others by exploring similar questions and additional content below.
Similar questions
  • SEE MORE QUESTIONS
Recommended textbooks for you
MATLAB: An Introduction with Applications
MATLAB: An Introduction with Applications
Statistics
ISBN:
9781119256830
Author:
Amos Gilat
Publisher:
John Wiley & Sons Inc
Probability and Statistics for Engineering and th…
Probability and Statistics for Engineering and th…
Statistics
ISBN:
9781305251809
Author:
Jay L. Devore
Publisher:
Cengage Learning
Statistics for The Behavioral Sciences (MindTap C…
Statistics for The Behavioral Sciences (MindTap C…
Statistics
ISBN:
9781305504912
Author:
Frederick J Gravetter, Larry B. Wallnau
Publisher:
Cengage Learning
Elementary Statistics: Picturing the World (7th E…
Elementary Statistics: Picturing the World (7th E…
Statistics
ISBN:
9780134683416
Author:
Ron Larson, Betsy Farber
Publisher:
PEARSON
The Basic Practice of Statistics
The Basic Practice of Statistics
Statistics
ISBN:
9781319042578
Author:
David S. Moore, William I. Notz, Michael A. Fligner
Publisher:
W. H. Freeman
Introduction to the Practice of Statistics
Introduction to the Practice of Statistics
Statistics
ISBN:
9781319013387
Author:
David S. Moore, George P. McCabe, Bruce A. Craig
Publisher:
W. H. Freeman