5. Suppose 100 steel rods are chosen at random from a large box of steel rods (more than 10,000). Suppose it is estimated that 5% are defective. The probabilities of the following events using the binomial distribution are below • P(A: none of the 100 widgets is defective) = 0.0059 • P(B: exactly 1 is defective) = 0.0371 • P(C: no more than 2 are defective) = 0.1183 • P(D: exactly 5 are defective) = 0.1800 • P(E: more than 5 are defective) <2.1*10-8 Use the Poison distribution to compute approximations to the same probabilities using a lambda value of 5 (.05*100)

MATLAB: An Introduction with Applications
6th Edition
ISBN:9781119256830
Author:Amos Gilat
Publisher:Amos Gilat
Chapter1: Starting With Matlab
Section: Chapter Questions
Problem 1P
icon
Related questions
Question
100%
**Problem 5: Probability Analysis Using Binomial and Poisson Distributions**

*Scenario:*
Assume 100 steel rods are selected randomly from a large box containing more than 10,000 steel rods. It is estimated that 5% of these rods are defective. The probabilities for various events are calculated using the binomial distribution.

*Probabilities:*
- **P(A):** Probability that none of the 100 rods is defective = 0.0059
- **P(B):** Probability that exactly 1 rod is defective = 0.0371
- **P(C):** Probability that no more than 2 rods are defective = 0.1183
- **P(D):** Probability that exactly 5 rods are defective = 0.1800
- **P(E):** Probability that more than 5 rods are defective < 2.1 * 10⁻⁸

*Task:*
Use the Poisson distribution to compute approximations for the same probabilities. Here, use a lambda value (λ) of 5, calculated as 5% of 100 (0.05 * 100).
Transcribed Image Text:**Problem 5: Probability Analysis Using Binomial and Poisson Distributions** *Scenario:* Assume 100 steel rods are selected randomly from a large box containing more than 10,000 steel rods. It is estimated that 5% of these rods are defective. The probabilities for various events are calculated using the binomial distribution. *Probabilities:* - **P(A):** Probability that none of the 100 rods is defective = 0.0059 - **P(B):** Probability that exactly 1 rod is defective = 0.0371 - **P(C):** Probability that no more than 2 rods are defective = 0.1183 - **P(D):** Probability that exactly 5 rods are defective = 0.1800 - **P(E):** Probability that more than 5 rods are defective < 2.1 * 10⁻⁸ *Task:* Use the Poisson distribution to compute approximations for the same probabilities. Here, use a lambda value (λ) of 5, calculated as 5% of 100 (0.05 * 100).
e. P(E: more than 5 are defective)
Transcribed Image Text:e. P(E: more than 5 are defective)
Expert Solution
trending now

Trending now

This is a popular solution!

steps

Step by step

Solved in 3 steps with 3 images

Blurred answer
Similar questions
Recommended textbooks for you
MATLAB: An Introduction with Applications
MATLAB: An Introduction with Applications
Statistics
ISBN:
9781119256830
Author:
Amos Gilat
Publisher:
John Wiley & Sons Inc
Probability and Statistics for Engineering and th…
Probability and Statistics for Engineering and th…
Statistics
ISBN:
9781305251809
Author:
Jay L. Devore
Publisher:
Cengage Learning
Statistics for The Behavioral Sciences (MindTap C…
Statistics for The Behavioral Sciences (MindTap C…
Statistics
ISBN:
9781305504912
Author:
Frederick J Gravetter, Larry B. Wallnau
Publisher:
Cengage Learning
Elementary Statistics: Picturing the World (7th E…
Elementary Statistics: Picturing the World (7th E…
Statistics
ISBN:
9780134683416
Author:
Ron Larson, Betsy Farber
Publisher:
PEARSON
The Basic Practice of Statistics
The Basic Practice of Statistics
Statistics
ISBN:
9781319042578
Author:
David S. Moore, William I. Notz, Michael A. Fligner
Publisher:
W. H. Freeman
Introduction to the Practice of Statistics
Introduction to the Practice of Statistics
Statistics
ISBN:
9781319013387
Author:
David S. Moore, George P. McCabe, Bruce A. Craig
Publisher:
W. H. Freeman