In 1996, McDonald's estimated that 10% of all American workers had worked at McDonald's at one point in their career (www.businessinsider.co m). Assume that 6 American workers are randomly selected, and that this can be modeled as a binomial distribution. What is the probability that exactly 2 of the 6 workers has worked at McDonald's? T T T Arial v 3 (12pt) TEE

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**Title: Understanding Probability with a Real-World Example**

In 1996, McDonald's estimated that 10% of all American workers had worked at McDonald's at one point in their career [source: Business Insider]. Assume that 6 American workers are randomly selected, and that this can be modeled as a binomial distribution.

**Problem Statement:**
What is the probability that exactly 2 out of the 6 workers have worked at McDonald's?

**Discussion:**

This problem requires the use of binomial distribution, which is suitable for scenarios with two possible outcomes (e.g., worked at McDonald's or not). The binomial distribution can model the number of successful outcomes in a set number of trials.

Here, the probability of success (a worker having worked at McDonald's) is 0.1, and we're interested in finding the probability of exactly 2 successes (workers) out of 6 trials. The formula to determine this is:

\[ P(X = k) = \binom{n}{k} \cdot p^k \cdot (1-p)^{n-k} \]

Where:
- \( n \) = total number of trials (6 workers)
- \( k \) = number of successes we’re interested in (2 workers)
- \( p \) = probability of success on a single trial (0.1)
- \(\binom{n}{k}\) = binomial coefficient

This type of calculation is common in statistics to determine likelihoods in various real-world scenarios.
Transcribed Image Text:**Title: Understanding Probability with a Real-World Example** In 1996, McDonald's estimated that 10% of all American workers had worked at McDonald's at one point in their career [source: Business Insider]. Assume that 6 American workers are randomly selected, and that this can be modeled as a binomial distribution. **Problem Statement:** What is the probability that exactly 2 out of the 6 workers have worked at McDonald's? **Discussion:** This problem requires the use of binomial distribution, which is suitable for scenarios with two possible outcomes (e.g., worked at McDonald's or not). The binomial distribution can model the number of successful outcomes in a set number of trials. Here, the probability of success (a worker having worked at McDonald's) is 0.1, and we're interested in finding the probability of exactly 2 successes (workers) out of 6 trials. The formula to determine this is: \[ P(X = k) = \binom{n}{k} \cdot p^k \cdot (1-p)^{n-k} \] Where: - \( n \) = total number of trials (6 workers) - \( k \) = number of successes we’re interested in (2 workers) - \( p \) = probability of success on a single trial (0.1) - \(\binom{n}{k}\) = binomial coefficient This type of calculation is common in statistics to determine likelihoods in various real-world scenarios.
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