What are the benefits of measuring the initial rate of a reaction V. for use in kinetic studies? (This is a multi-select question). [ES] can be measured accurately. changes in [S] are negligible, so the value of [S] is known. changes in Km are negligible, so Km can be treated as a constant. Ovo = Vmax. A negligible amount of product has formed, so that the back reaction P --> ES need not be considered.
What are the benefits of measuring the initial rate of a reaction V. for use in kinetic studies? (This is a multi-select question). [ES] can be measured accurately. changes in [S] are negligible, so the value of [S] is known. changes in Km are negligible, so Km can be treated as a constant. Ovo = Vmax. A negligible amount of product has formed, so that the back reaction P --> ES need not be considered.
Biochemistry
9th Edition
ISBN:9781319114671
Author:Lubert Stryer, Jeremy M. Berg, John L. Tymoczko, Gregory J. Gatto Jr.
Publisher:Lubert Stryer, Jeremy M. Berg, John L. Tymoczko, Gregory J. Gatto Jr.
Chapter1: Biochemistry: An Evolving Science
Section: Chapter Questions
Problem 1P
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![What are the benefits of measuring the initial rate of a reaction Vå for use in kinetic
studies? (This is a multi-select question).
[ES] can be measured accurately.
changes in [S] are negligible, so the value of [S] is known.
changes in Km are negligible, so Km can be treated as a constant.
V₁ = Vmax.
-->
A negligible amount of product has formed, so that the back reaction P --
need not be considered.
ES](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F600ac1ec-d0a5-4eba-8236-8124537338a5%2F67366d8b-2714-46b3-a3d2-179b4fb29026%2F9z7yiwn_processed.jpeg&w=3840&q=75)
Transcribed Image Text:What are the benefits of measuring the initial rate of a reaction Vå for use in kinetic
studies? (This is a multi-select question).
[ES] can be measured accurately.
changes in [S] are negligible, so the value of [S] is known.
changes in Km are negligible, so Km can be treated as a constant.
V₁ = Vmax.
-->
A negligible amount of product has formed, so that the back reaction P --
need not be considered.
ES
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