What amino acid is coded by each codon? Note: Reference the Genetic code table for additional information. Part 1 of 4 CAC Part 2 of 4 CAA Part 3 of 4 GUA Part 4 of 4 GAA ☑ ☑ ☑
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- For each codon, provide the anticodon and the three-letter abbreviation of the amino acid for which it codes. Consult the codon table as needed. 5'-AUU-3' anticodon: 3'- -5' amino acid: 5' -UCU-3' anticodon: 3'- -5' amino acid: 5' -CAG-3' anticodon: 3'- -5' amino acid:For the following mRNA sequences, what is the amino acid sequence formed? Consult genetic code table for reference. 5' AGUCCGUAC 3' 5' AAUUGCUUC 3'Indicate the amino acid sequence of the protein encoded by the following mRNA molecule. Use the genetic code table and assume that the very first “AUG” the ribosome encounters will serve as the start codon and specify methionine. 5’-AAUUCAUGCCCAAAUUUGGGGCACGAAGCUUCUUAGGCUAGUCCUAAAAAA-3’
- Codons in the set CUU, CUC, CUA, and CUG all code for the amino acid leucine. In this set, the first and second bases are identical; the identity of the third base is irrelevant. For what other sets of codons is the third base also irrelevant? For what amino acid(s) does each set code?Consider the following original coding sequence of a gene that codes for a short 5- amino acid polypeptide: 5'-ATGGGCTCGAACTCATAA-3' Using the genetic code and the amino acid table below, which of the following sequences arises from a non-conservative missense mutation in the original sequence shown above? First base in codon U U A UUU UUC- UUA UUG- CUU CUC CUA CUG- U Phe (F) Leu (L) Leu (L) Second base in codon Val (V) UCU - UCC UCA UCG CCU CCC CCA CCG AUU ACU- AUC Ile (1) ACC AUA- ACA AUG Met (M) start ACG GUU GCU- GUC GCC GUA GCA GUG GCG- C Ser (S) Pro (P) Thr (T) Ala (A) UAU UAC UAAT UAG CAU CAC CAA CAG AAU AAC AAA AAG GAU GAC GAA GAG A Tyr (Y) STOP His (H) Gln (Q) Asn (N) Lys (K) Asp (D) Glu (E) G UGU UGC UGA STOP UGG Trp (W) Cys (C) CGU CGC CGA CGG AGU AGC AGA 1 AGG GGU- GGC GGA GGG Arg (R) Ser (S) Arg (R) Gly (G) U C A G U C A G U C A G U C A G Last base in codonList all possible codons present in a ribonucleotide polymer containing U and G in random sequence. Which amino acids are encoded by this RNA?
- Use the genetic code table. Which amino acid is coded for by only one codon sequence? Second Position U A G UUU Phe /F UCU UAU UGU UUC Tyr/Y Cys/C UCC UAC UGC Ser /s UUA Leu /L UCA UAA STOP UGA STOP UUG UCG UAG STOP UGG CUU CCU CAU CGU CỤC His / H Leu /L CC САС Pro / P CGC CUA ССА Arg/R CAA CGA CUG Gln /Q CCG CAG CGG AUU ACU AAU AGU AUC le /i ACC Asn / N Ser /S Thr/T AAC AGC AUA ACA AAA AGA AUG Met / M ACG Lys/K Arg/R AAG AGG GUU GCU GAU GGU GUC Asp/ D G Val /v GCC Ala / A GAC GGC GUA GCA Gly/G GAA GGA GUG GCG Glu /E GAG GGG valine serine threonine isoleucine methionine MacBook PrO G Search or type URL +, #3 Third Position SCAG UCAGU CAGU CA First PositionConsider the mRNA sequence below. Assume that the following mRNA segment has been translated. 5'-GCAAGUCUUAAU-3' Note for numbers 1 and 2: Use the three-letter abbreviation of amino acid; separate amino acids with a hyphen: do not include the stop codon. Example: ala-cys-glu 1. Using the table of the genetic code, determine the sequence of amino acids. ala-ser-leu-asn 2. If mutation occurs by substitution of the 6th nucleotide with adenosine-5'- monophosphate, what is the resulting amino acid sequence? 3. What type of mutation occurred? Choose from same sense, missense and non-sense.a) b) Shown below is a DNA sequence that encodes for a section of a protein. Please write the amino acid sequence using the three letter codes for this section. 5' ATG ACT CTC TCC TGG GGC ATC CGA TAA 3' What would the second codon be changed to if it was both a silent mutation and a transition mutation? Please write an anticodon in 5' to 3' direction that would recognize both the original second codon and the mutated second codon.
- Several experiments were conducted to obtain information about how the eukaryotic ribosome recognizes the AUG start codon. In one experiment, the gene that encodes methionine initiator tRNA (tRNAiMet) was located and changed; specifically, the nucleotides that specify the anticodon on tRNAi Met were mutated so that the anticodon in the tRNA was 5′ –CCA–3′ instead of 5′ –CAU–3′. When this mutated gene was placed in a eukaryotic cell, protein synthesis took place, but the proteins produced were abnormal. Some of these proteins contained extra amino acids, and others contained fewer amino acids than normal. a. What do these results indicate about how the ribosome recognizes the starting point for translation in eukaryotic cells? Explain your reasoning. b. If the same experiment had been conducted on bacterial cells, what results would you expect? c. Explain why some of the proteins produced contained extra amino acids while others contained fewer amino acids than normalSeveral experiments were conducted to obtain information about how the eukaryotic ribosome recognizes the AUG start codon. In one experiment, the gene that encodes methionine initiator tRNA (tRNAiMet) was located and changed; specifically, the nucleotides that specify the anticodon on tRNAiMet were mutated so that the anticodon in the tRNA was 5′ –CCA–3′ instead of 5′ –CAU–3′. When this mutated gene was placed in a eukaryotic cell, protein synthesis took place, but the proteins produced were abnormal. Some of these proteins contained extra amino acids, and others contained fewer amino acids than normal. Q. What do these results indicate about how the ribosome recognizes the starting point for translation in eukaryotic cells? Explain your reasoning.Several experiments were conducted to obtain information about how the eukaryotic ribosome recognizes the AUG start codon. In one experiment, the gene that encodes methionine initiator tRNA (tRNAiMet) was located and changed; specifically, the nucleotides that specify the anticodon on tRNAiMet were mutated so that the anticodon in the tRNA was 5′ –CCA–3′ instead of 5′ –CAU–3′. When this mutated gene was placed in a eukaryotic cell, protein synthesis took place, but the proteins produced were abnormal. Some of these proteins contained extra amino acids, and others contained fewer amino acids than normal. Q. If the same experiment had been conducted on bacterial cells, what results would you expect?