We started with 20 mL 1 M acetic acid ~ 0.020 L acetic acid in a flask. (Ka acetic acid = 1.8x10^-5; pKa = 4.7) (Kb ammonia = 1.8x10^-5; pKb = 4.7; Ka = 5.56x10^-10; pKa = 9.25) We titrated with 1 M Ammonia have to calculate the pH mathematically at different amounts of Ammonia added. Our Ammonia amounts are 8 mL, 16 mL, 20 mL, and 22 mL. We then have to find the percent difference of the online labs pH calculations. Online Lab's Values: 8 mL Ammonia - pH of 4.58 16 mL Ammonia - pH of 5.36 20 mL Ammonia - pH of 6.99 (equivalence point in the lab) 22 mL Ammonia - pH of 8.24
Please don't copy I am completing an online lab so I will try to provide the needed information to solve. Please let me know if any information is missing.
We started with 20 mL 1 M acetic acid ~ 0.020 L acetic acid in a flask.
(Ka acetic acid = 1.8x10^-5; pKa = 4.7) (Kb ammonia = 1.8x10^-5; pKb = 4.7; Ka = 5.56x10^-10; pKa = 9.25)
We titrated with 1 M Ammonia have to calculate the pH mathematically at different amounts of Ammonia added. Our Ammonia amounts are 8 mL, 16 mL, 20 mL, and 22 mL.
We then have to find the percent difference of the online labs pH calculations.
Online Lab's Values:
8 mL Ammonia - pH of 4.58
16 mL Ammonia - pH of 5.36
20 mL Ammonia - pH of 6.99 (equivalence point in the lab)
22 mL Ammonia - pH of 8.24
I would greatly appreciate if you could show for all 4 of the amounts of Ammonia added, and show how you did them.
Thank you! Will gladly upvote if work is shown!
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