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vs (t) + I 402 ww R₁ iL (t) 17 cos(500t+45°) V R₁₂102 L8mH C 0.4mF After transforming the series (vs (t) + R₁) to a parallel current source and resistor (is (t) || R1), Total admittance YT-Ex: 0.11 -j S Inductor current IL = iL(t): = Ex: 11.1 A 0 cos (Ex: 1 t- °) A

vs (t) + I 402 ww R₁ iL (t) 17 cos(500t+45°) V R₁₂102 L8mH C 0.4mF After transforming the series (vs (t) + R₁) to a parallel current source and resistor (is (t) || R1), Total admittance YT-Ex: 0.11 -j S Inductor current IL = iL(t): = Ex: 11.1 A 0 cos (Ex: 1 t- °) A

Introductory Circuit Analysis (13th Edition)
Introductory Circuit Analysis (13th Edition)
13th Edition
ISBN:9780133923605
Author:Robert L. Boylestad
Publisher:Robert L. Boylestad
Chapter1: Introduction
Section: Chapter Questions
Problem 1P: Visit your local library (at school or home) and describe the extent to which it provides literature...
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vs (t) + I 402 ww R₁ iL (t) 17 cos(500t+45°) V R₁₂102 L8mH C 0.4mF After transforming the series (vs (t) + R₁) to a parallel current source and resistor (is (t) || R1), Total admittance YT-Ex: 0.11 -j S Inductor current IL = iL(t): = Ex: 11.1 A 0 cos (Ex: 1 t- °) A
Transcribed Image Text:vs (t) + I 402 ww R₁ iL (t) 17 cos(500t+45°) V R₁₂102 L8mH C 0.4mF After transforming the series (vs (t) + R₁) to a parallel current source and resistor (is (t) || R1), Total admittance YT-Ex: 0.11 -j S Inductor current IL = iL(t): = Ex: 11.1 A 0 cos (Ex: 1 t- °) A
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